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sark123
 one year ago
In the bet on a “single number” at roulette, there is chance 1/38 of winning. The bet pays 35 to 1; you can take this to mean that if you win the bet, your net gain is $35, and if you lose the bet then you lose $1 (that is, your net gain is $1). Suppose you bet repeatedly on a single number; assume that the bets are independent of each other. Find the expected value of your net gain from 38 bets.
sark123
 one year ago
In the bet on a “single number” at roulette, there is chance 1/38 of winning. The bet pays 35 to 1; you can take this to mean that if you win the bet, your net gain is $35, and if you lose the bet then you lose $1 (that is, your net gain is $1). Suppose you bet repeatedly on a single number; assume that the bets are independent of each other. Find the expected value of your net gain from 38 bets.

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bubblemath122
 one year ago
Best ResponseYou've already chosen the best response.0Expected value = (1/38) *35 + (37/38)(1) = 1/19 which is around $0.05 now multiply that by 38 so 1/19 * 38 = 2

bubblemath122
 one year ago
Best ResponseYou've already chosen the best response.0you will expect a net loss of 2 dollars on 38 bets

sark123
 one year ago
Best ResponseYou've already chosen the best response.0thumbs up for you man !

pandu
 one year ago
Best ResponseYou've already chosen the best response.0In the bet on a “single number” at roulette, there is chance 1/38 of winning. The bet pays 35 to 1; you can take this to mean that if you win the bet, your net gain is $35, and if you lose the bet then you lose $1 (that is, your net gain is $1). You don’t need to know any more about roulette to solve this problem, but the description given above is what would happen if you were to bet $1 on a single number at a Las Vegas roulette table. Suppose you bet repeatedly on a single number; assume that the bets are independent of each other. Find the expected value of your net gain from 38 bets
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