A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Open

LolWolf
 one year ago
Best ResponseYou've already chosen the best response.3Note that this is: \[ \frac{d}{dT}\frac{A}{T}=\frac{dA}{dT}\cdot\frac{d}{dT}\left(\frac{1}{T}\right) \]This becomes: \[ \frac{dA}{dT}\cdot\frac{1}{T^2} \]And, I can take a guess, although I don't quite know what \(A\) is in this context, we have: \[ \frac{dA}{dT}=E \]So: \[ E\cdot\frac{1}{T^2}=\frac{E}{T^2} \]

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.0A is the Helmholtz energy, A for Arbeit in German, E or mostly written U is the internal energy.

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.0True most of the way except that: \[A=UTS\] \[\left( \frac{ \partial A }{ \partial T } \right)_{V}=S\] S is the entropy.

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.0But if you substitute the equations back and forth you come to the conclusion you did so well done by lolwolf.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.