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chemcalc

hh

  • 11 months ago
  • 11 months ago

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  1. nincompoop
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    I don't know what you're trying to do.

    • 11 months ago
  2. chemcalc
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    @nincompoop the Element Ir = e + what?

    • 11 months ago
  3. nincompoop
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    could you elaborate what your question is asking? how many electrons does element Iridium have? well in nature, elements are neutral, this means that the number of protons and electrons are equal. look at your periodic table and see how many protons it has, then use that as a reference to indicate how many electrons.

    • 11 months ago
  4. chemcalc
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    As shown on the periodic table, it looks like 192 Ir 77 Now what makes that result if one electron is added @nincompoop

    • 11 months ago
  5. nincompoop
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    Iridium has 77 protons therefore it has 77 electrons the amu is 192 atomic weight = protons + neutrons the + charge indicates that one electron is removed this is why there's more protons (+) than electrons (-). if 1 electron is removed then you would have: \[_{77}^{192}Ir^+=76e^-\]

    • 11 months ago
  6. nincompoop
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    now if it were: \[_{77}^{192} Ir^-=78e^-\]

    • 11 months ago
  7. nincompoop
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    do you understand @chemcalc ?

    • 11 months ago
  8. chemcalc
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    yes @nincompoop

    • 11 months ago
  9. nincompoop
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    let me test what you've learned. how many electrons does an iridium have when: \[_{77}^{192}Ir^{+2}\] and when: \[_{77}^{192}Ir^{-4}\]

    • 11 months ago
  10. chemcalc
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    75e 81e @nincompoop

    • 11 months ago
  11. nincompoop
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    super! learn something more: ISOELECTRIC this means that Iridium is now isoelectric (the same number of electrons/configuration) as Rhenium (Re) when its electron is 75, and isoelectric as Thallium (Tl) when its electron is 81.

    • 11 months ago
  12. chemcalc
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    Wow, thank you ! @nincompoop

    • 11 months ago
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