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DaWizjr Group Title

Find S20 when t1 = 4 and d = 5

  • one year ago
  • one year ago

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  1. DaWizjr Group Title
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    Now you have to use formula

    • one year ago
  2. DaWizjr Group Title
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    tn=t1+(n-1)d

    • one year ago
  3. Shadowys Group Title
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    \(S_{n}=\frac{n}{2} (2 t_1 + (n-1)d)\) sub n=20, and everything you've got there. do u need further help?

    • one year ago
  4. DaWizjr Group Title
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    cool

    • one year ago
  5. DaWizjr Group Title
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    S(20=20/2(2(4)+(20-1)5)

    • one year ago
  6. DaWizjr Group Title
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    And how would I work this out @Shadowys

    • one year ago
  7. Shadowys Group Title
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    um,simplify this then. \(\frac{20}{2}[(2)(4)+(20-1)5]=10[8+19(5)]\) what follows can be done by manual arithmetic or a calculator.

    • one year ago
  8. DaWizjr Group Title
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    I got 1030

    • one year ago
  9. Shadowys Group Title
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    yup, that's what I got too. :)

    • one year ago
  10. DaWizjr Group Title
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    Cool

    • one year ago
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