DaWizjr
Find S20 when t1 = 4 and d = 5



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DaWizjr
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Now you have to use formula

DaWizjr
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tn=t1+(n1)d

Shadowys
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\(S_{n}=\frac{n}{2} (2 t_1 + (n1)d)\)
sub n=20, and everything you've got there.
do u need further help?

DaWizjr
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cool

DaWizjr
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S(20=20/2(2(4)+(201)5)

DaWizjr
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And how would I work this out @Shadowys

Shadowys
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um,simplify this then.
\(\frac{20}{2}[(2)(4)+(201)5]=10[8+19(5)]\)
what follows can be done by manual arithmetic or a calculator.

DaWizjr
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I got 1030

Shadowys
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yup, that's what I got too. :)

DaWizjr
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Cool