anonymous
  • anonymous
Find S20 when t1 = 4 and d = 5
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Now you have to use formula
anonymous
  • anonymous
tn=t1+(n-1)d
anonymous
  • anonymous
\(S_{n}=\frac{n}{2} (2 t_1 + (n-1)d)\) sub n=20, and everything you've got there. do u need further help?

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anonymous
  • anonymous
cool
anonymous
  • anonymous
S(20=20/2(2(4)+(20-1)5)
anonymous
  • anonymous
And how would I work this out @Shadowys
anonymous
  • anonymous
um,simplify this then. \(\frac{20}{2}[(2)(4)+(20-1)5]=10[8+19(5)]\) what follows can be done by manual arithmetic or a calculator.
anonymous
  • anonymous
I got 1030
anonymous
  • anonymous
yup, that's what I got too. :)
anonymous
  • anonymous
Cool

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