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DaWizjr

  • 3 years ago

Find S20 when t1 = 4 and d = 5

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  1. DaWizjr
    • 3 years ago
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    Now you have to use formula

  2. DaWizjr
    • 3 years ago
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    tn=t1+(n-1)d

  3. Shadowys
    • 3 years ago
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    \(S_{n}=\frac{n}{2} (2 t_1 + (n-1)d)\) sub n=20, and everything you've got there. do u need further help?

  4. DaWizjr
    • 3 years ago
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    cool

  5. DaWizjr
    • 3 years ago
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    S(20=20/2(2(4)+(20-1)5)

  6. DaWizjr
    • 3 years ago
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    And how would I work this out @Shadowys

  7. Shadowys
    • 3 years ago
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    um,simplify this then. \(\frac{20}{2}[(2)(4)+(20-1)5]=10[8+19(5)]\) what follows can be done by manual arithmetic or a calculator.

  8. DaWizjr
    • 3 years ago
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    I got 1030

  9. Shadowys
    • 3 years ago
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    yup, that's what I got too. :)

  10. DaWizjr
    • 3 years ago
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    Cool

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