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DaWizjr Group TitleBest ResponseYou've already chosen the best response.0
Now you have to use formula
 one year ago

DaWizjr Group TitleBest ResponseYou've already chosen the best response.0
tn=t1+(n1)d
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
\(S_{n}=\frac{n}{2} (2 t_1 + (n1)d)\) sub n=20, and everything you've got there. do u need further help?
 one year ago

DaWizjr Group TitleBest ResponseYou've already chosen the best response.0
S(20=20/2(2(4)+(201)5)
 one year ago

DaWizjr Group TitleBest ResponseYou've already chosen the best response.0
And how would I work this out @Shadowys
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
um,simplify this then. \(\frac{20}{2}[(2)(4)+(201)5]=10[8+19(5)]\) what follows can be done by manual arithmetic or a calculator.
 one year ago

DaWizjr Group TitleBest ResponseYou've already chosen the best response.0
I got 1030
 one year ago

Shadowys Group TitleBest ResponseYou've already chosen the best response.1
yup, that's what I got too. :)
 one year ago
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