Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

urgent help needed pls help

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
is uninhibited decay the same as exponential decay ?
i am not sure @UnkleRhaukus

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[\big[\text{NaCl}\big](t) = \big[\text{NaCl}\big]_0e^{-t/\tau}\]
\[\frac{\big[\text{NaCl}\big](t)}{\big[\text{NaCl}\big]_0} = e^{-t/\tau}\\ \ln\tfrac{\big[\text{NaCl}\big](t)}{\big[\text{NaCl}\big]_0} = -t/\tau\\ \tau\ln\tfrac{\big[\text{NaCl}\big]_0}{\big[\text{NaCl}\big](t)} = t\\\tau = \frac t{\ln\tfrac{\big[\text{NaCl}\big]_0}{\big[\text{NaCl}\big](t)}}\]
what do you think?
@UnkleRhaukus i don't get what u wrote
any of it?
do you know where i got the original equation from ?
\[A=A _{0}e ^{-kt}\]
@UnkleRhaukus pls could u help with this question
1 Attachment
tangent negative, sin positive puts you in quadrant II
|dw:1367156027644:dw|
@UnkleRhaukus for the above question pls can u draw the equation because the equation u wrote is in wierd computer language form its really urgent pls help thanks
i found \[\tau=\tfrac1k\sim1 \text{day} \]

Not the answer you are looking for?

Search for more explanations.

Ask your own question