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ketz

  • 2 years ago

f=x'y'z+(x'y'z)'. Simplify the boolean expression.

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  1. ketz
    • 2 years ago
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    It's urgent...

  2. jack63
    • 2 years ago
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    hi please reput this question in the math section

  3. hartnn
    • 2 years ago
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    your next math questions should go in http://openstudy.com/study#/groups/mathematics as for this, you use the identity, A+A' = 1 so, f=x'y'z+(x'y'z)' = 1 (where x'y'z can be considered as A)

  4. jack63
    • 2 years ago
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    hey @hartnn

  5. hartnn
    • 2 years ago
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    hi, jack :)

  6. jack63
    • 2 years ago
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    came back from long training

  7. hartnn
    • 2 years ago
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    welcome back! great to have you again on OS :)

  8. jack63
    • 2 years ago
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    i happy to be back and i missed all my friends on os. that means u to

  9. hartnn
    • 2 years ago
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    :)

  10. jack63
    • 2 years ago
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    so how was everything when i was gone

  11. hartnn
    • 2 years ago
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    lets not talk here, its a question...

  12. jack63
    • 2 years ago
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    true so were should we talk

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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