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ketz
Group Title
f=x'y'z+(x'y'z)'. simplify the boolean expression. urgent
 one year ago
 one year ago
ketz Group Title
f=x'y'z+(x'y'z)'. simplify the boolean expression. urgent
 one year ago
 one year ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.1
you use the identity, A+A' = 1 so, f=x'y'z+(x'y'z)' = 1 (where x'y'z can be considered as A)
 one year ago

ketz Group TitleBest ResponseYou've already chosen the best response.0
but if i proceed by expanding the bracket! I'm not getting the answer!!!!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
expanding the bracket ? like x'y'z +xyz' ? no need for that, you can use A=x'y'z and that A+A'=1 you can also verify it using truth table.
 one year ago

ketz Group TitleBest ResponseYou've already chosen the best response.0
yeh i know but i want to proceed by expanding the bracket using de morgan's laws. and am not getting the answer. can anyone try it by this method!!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
let me try on, left of + x'y' = (x+y)' > x'y'z =(x+y)'z on right of + (x'y'z)' = (x+y+z') hmm
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
f=x'y'z+(x'y'z)' x'y'z + x + y + z' y'z + x + y + z' x + y'z + y + z' x + y + z + z' x + y + 1 1
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
in 2ns line use this rule : x+x'y = x+y
 one year ago

ketz Group TitleBest ResponseYou've already chosen the best response.0
Can you prove the law x+x'y=x+y???
 one year ago

ketz Group TitleBest ResponseYou've already chosen the best response.0
By Boolean Algebra!
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
did u try to prove already... it wont be difficult i think
 one year ago

ketz Group TitleBest ResponseYou've already chosen the best response.0
How can you prove or simplify it by boolean algebra??
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
do u knw distributive property for AND logic ?
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
x + (y.z) = (x+y).(x+z)
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
u familiar wid that prop ? u can use that to prove x + x'y = x + y very easily
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.3
great :)
 one year ago
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