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emcrazy14 2 years ago Quick Question: Forces of magnitude 10 N and 8 N act in the direction shown. Write down in terms of theta, the component of the resultant of two forces: a) parallel to the force of magnitude 10N b) perpendicular to the force of magnitude 10N.

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1. emcrazy14

2. marco26

Do summation of forces along the horizontal and vertical (x and y). Summation of forces along x will give you the answer to question A and y to B

3. Shadowys

$$\vec F_1=8(-\cos \theta \hat a_x + \sin \theta \hat a_y)$$ $$\vec F_2=10 \hat a_x$$ adding gives $$\vec F=(10-8 \cos \theta) \hat a_x + 8 \sin \theta \hat a_y$$ so the component parallel is $$(10-8 \cos \theta)$$ and perpendicular is$$8 \sin \theta$$

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