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 one year ago
Quick Question:
Forces of magnitude 10 N and 8 N act in the direction shown.
Write down in terms of theta, the component of the resultant of two forces:
a) parallel to the force of magnitude 10N
b) perpendicular to the force of magnitude 10N.
 one year ago
Quick Question: Forces of magnitude 10 N and 8 N act in the direction shown. Write down in terms of theta, the component of the resultant of two forces: a) parallel to the force of magnitude 10N b) perpendicular to the force of magnitude 10N.

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marco26
 one year ago
Best ResponseYou've already chosen the best response.0Do summation of forces along the horizontal and vertical (x and y). Summation of forces along x will give you the answer to question A and y to B

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1\(\vec F_1=8(\cos \theta \hat a_x + \sin \theta \hat a_y)\) \(\vec F_2=10 \hat a_x \) adding gives \(\vec F=(108 \cos \theta) \hat a_x + 8 \sin \theta \hat a_y\) so the component parallel is \((108 \cos \theta)\) and perpendicular is\(8 \sin \theta\)
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