## emcrazy14 Group Title Quick Question: Forces of magnitude 10 N and 8 N act in the direction shown. Write down in terms of theta, the component of the resultant of two forces: a) parallel to the force of magnitude 10N b) perpendicular to the force of magnitude 10N. one year ago one year ago

$$\vec F_1=8(-\cos \theta \hat a_x + \sin \theta \hat a_y)$$ $$\vec F_2=10 \hat a_x$$ adding gives $$\vec F=(10-8 \cos \theta) \hat a_x + 8 \sin \theta \hat a_y$$ so the component parallel is $$(10-8 \cos \theta)$$ and perpendicular is$$8 \sin \theta$$