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leena1996
The following data were obtained in an experiment on inversion of cane sugar in the presence of 0.1N HCl. Time(min) 0 60 120 180 360 infinity Angle of Rotation 13.1 11.6 10.2 9.0 5.87 -3.8 After what time would you expect a zero reading in Polarimeter........its urgent can someone help me fast!
WOW Very interesting question i Love it :)
@chmvijay will u plz solve it.....
yup it is theorotical just use chemical kinetics and answer this @nincompoop
hope @nincompoop answers this :)
me too hopind the same......lets see...its not supposed to be very difficult .... it is class 12 question....ISC board @chmvijay
ok here's the only hint formula\[k =\frac{ 2.303 }{ t }\log_{10}\frac{ r_{0}-r _{\infty} }{ r_{t}-r _{\infty} } \]
@nincompoop @chmvijay @Frostbite i got to go back to work.......if you guys get the answer plz do reply here........thanks! Bye will be back soon
ok fine me to leaving to BED will see it hope @nincompoop solves this :)
I guess i will have to ask this to my instructor...!
in the formula \[k={2.303\over t}\log_{10}\frac{r_0-r_\infty}{r_t-r_\infty}\] k = rate of reaction (interms of change in optical activity) t = time r = angles of rotation from this, we calculate the rate of reaction \[ k={2.303\over120}\log_{10}\frac{13.1-(-3.8)}{10.2-(-3.8)}\\ k=1.57\times10^{-3} \] use the equation again, to find "t" when r_t=0 rearranging, the terms, \[ t={2.303\over 0.00157}\log_{10}\frac{13.1-(-3.8)}{0-(-3.8)}\\ \Large\boxed{t=950\,{\rm min}\\ t=15\,{\rm hr}\;50\,{\rm min}} \]
@electrokid Thanks a lot!!! It was great help....