Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

consider the bases B=[u1,u2] and B'[v1,v2] for R^2, where u1=[1 0], u2 [0 1], v1=[2 1], v2=[-3 4]. its matrix 1x2. how to find the transition matrix from B' to B and the other way around? also, compute the coordinate vector [w]b where w=[3 -5] and use (9) to compute [w]b'

Linear Algebra
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

hey, friend, we have formula to find the transition matrix from b' to B. B is the new place you want to come there, so put B first in |B|B'| and make them become | I | some new matrix| . the last "some new matrix" is matrix transition from B' to B, denoted by P_(B' to B) and if you want to have the matrix transition from B to B', just take P inverse. To compute [W]_B , you must do something like W = C1*u1 + C2 * u2 = (3,-5) (actually, it's not hard , hopefully you know how to get this) after have [w]B, use inverse transition matrix to calculate [W}B' by putting into the formula P^- * [W]B hopefully you understand my English

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question