Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing
Let V be vector space with dim(V)=n and T:V>V a linear operator. If y is an eigenvalue of T with geometric multiplicity n, then show that every nonzero vector of V is an eigenvector.
I have no idea how to prove. I think I have to use the definition of Eigenvalues and Eigenvectors of Linear Operators but not sure how.
 11 months ago
 11 months ago
Let V be vector space with dim(V)=n and T:V>V a linear operator. If y is an eigenvalue of T with geometric multiplicity n, then show that every nonzero vector of V is an eigenvector. I have no idea how to prove. I think I have to use the definition of Eigenvalues and Eigenvectors of Linear Operators but not sure how.
 11 months ago
 11 months ago

This Question is Open
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.