Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

zbowman75

  • 3 years ago

Let V be vector space with dim(V)=n and T:V->V a linear operator. If y is an eigenvalue of T with geometric multiplicity n, then show that every nonzero vector of V is an eigenvector. I have no idea how to prove. I think I have to use the definition of Eigenvalues and Eigenvectors of Linear Operators but not sure how.

  • This Question is Open

    Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy