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Khlara

  • one year ago

A class has 3 Teaching Assistants (TAs). Each TA tosses a coin 10 times. Find the chance that at least one of the TAs gets exactly 5 heads. unanswered

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  1. dan815
    • one year ago
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    or in other words what is the probability when no TA gets 5 heads

  2. dan815
    • one year ago
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    @FibonacciChick666 help us with this

  3. FibonacciChick666
    • one year ago
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    k so lets make a chart with the outcomes

  4. FibonacciChick666
    • one year ago
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    strike that cause it will take forever ok what is the probability that 1 TA will get exactly 5 heads?

  5. dan815
    • one year ago
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    im thinking its like this for 1 TA

  6. dan815
    • one year ago
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    i dunno im kinda confused about this whole thing

  7. FibonacciChick666
    • one year ago
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    hmm let me think.... ughh I'm so annoyed we did this in 6th grade why can't I remember...

  8. FibonacciChick666
    • one year ago
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    at least not all 3 duh ok

  9. FibonacciChick666
    • one year ago
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    ok so you would think that it would be more likely right

  10. dan815
    • one year ago
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    hmm

  11. FibonacciChick666
    • one year ago
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    but coins are weird because the prob for hhhhhh= prob for tthhtt

  12. dan815
    • one year ago
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    is itt like this

  13. dan815
    • one year ago
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    for 1 TA getting 5 heads

  14. dan815
    • one year ago
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    |dw:1367217339549:dw|

  15. FibonacciChick666
    • one year ago
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    i'm thinking \[the~probability~for~1~TA~is~ (\frac{1}{2})^5\]because they have to be in a row

  16. dan815
    • one year ago
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    but it says they just need to get 5 outta 10

  17. FibonacciChick666
    • one year ago
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    oh shoot hmm well that would be one half to the 10th that tells us the total combinations

  18. FibonacciChick666
    • one year ago
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    then we take out anything that has more than 4 tails

  19. FibonacciChick666
    • one year ago
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    5*

  20. FibonacciChick666
    • one year ago
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    but we need permutations don't we

  21. dan815
    • one year ago
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    i think u are right (1/2)^5 for 1 TA

  22. FibonacciChick666
    • one year ago
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    if that is right then if we cubed it that would be for all three to get it but if we added them that would be for 1 right?

  23. dan815
    • one year ago
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    that (1/2)^5 * 3 for 1 of the 3 having 5 heads gotta add the probability of 2 of them getting 5 heads and 3 getting 5 heads so + [(1/2^5)^2] *3 + [(1/2^5)^3]

  24. dan815
    • one year ago
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    yeah all probability gotta equal 1

  25. FibonacciChick666
    • one year ago
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    can't equal one

  26. dan815
    • one year ago
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    im not sure though if the probability shud be 1/2^5

  27. FibonacciChick666
    • one year ago
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    neither am I let me call in @hero

  28. dan815
    • one year ago
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    does that look right for a dice if that is right then i guess u can just use that way for the coin too

  29. FibonacciChick666
    • one year ago
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    ok... hmm that looks right but i'm just not sure it's been so long since i've taken prob and stats

  30. FibonacciChick666
    • one year ago
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    you need to learn to write in LaTex...

  31. dan815
    • one year ago
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    what is that

  32. FibonacciChick666
    • one year ago
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    http://openstudy.com/study#/groups/LaTeX%20Practicing!%20%3A) you can learn it here

  33. FibonacciChick666
    • one year ago
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    but pretty much \[you~write~like~this~for~math~stuff~~~~~~~~~~[\frac{1}{2}]^5\\]

  34. FibonacciChick666
    • one year ago
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    \[you~write~like~this~for~math~stuff~~~~~~~~~~[\frac{1}{2}]^5\]

  35. dan815
    • one year ago
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    do you just type that out or use Equation button down there

  36. FibonacciChick666
    • one year ago
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    type it out

  37. dan815
    • one year ago
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    o wow lol

  38. FibonacciChick666
    • one year ago
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    it is a free program for writing in math

  39. FibonacciChick666
    • one year ago
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    but that is the same as using the eq button down there

  40. dan815
    • one year ago
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    hbey I THINK I GOT IT NOW

  41. FibonacciChick666
    • one year ago
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    sweet

  42. dan815
    • one year ago
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    |dw:1367219586841:dw|

  43. FibonacciChick666
    • one year ago
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    the answer cant be one...

  44. dan815
    • one year ago
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    |dw:1367219732506:dw|

  45. dan815
    • one year ago
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    no mean 1 - whatever that is equal to is our answer

  46. FibonacciChick666
    • one year ago
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    ohhhhh uhm maybe i honestly stopped thinking about it

  47. dan815
    • one year ago
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    i think iam addicted to these questions, i cant stop till i solve when someone asks these questions lol its gonna bug me for ever

  48. FibonacciChick666
    • one year ago
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    i know but it's 3 am here...

  49. dan815
    • one year ago
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    so are u on summer vacaation yet

  50. FibonacciChick666
    • one year ago
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    yep :) for 2 weeks then summer classes you?

  51. dan815
    • one year ago
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    nice, i got time till summer classes, my summer classes is in 2nd term of summer dunno when that is

  52. FibonacciChick666
    • one year ago
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    lucky i have like 28 credits over the summer :/

  53. dan815
    • one year ago
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    wow u took way too much in summer lol

  54. dan815
    • one year ago
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    how are u gonna keep up! is ur summer term as long as the regular term

  55. FibonacciChick666
    • one year ago
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    uhm kind of.... i'm not sure though cause i also work like 35 hours a week

  56. dan815
    • one year ago
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    i dont think id be able to do it, unless its like all electives

  57. dan815
    • one year ago
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    even then its gotta be some super easy BS on exam electives

  58. FibonacciChick666
    • one year ago
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    i have PDE, single variable calc proofs, a linguistics intro course, an art class, cog. psych, and more that i forget lol

  59. dan815
    • one year ago
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    oo PDE :)

  60. dan815
    • one year ago
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    MATH MAJOR

  61. FibonacciChick666
    • one year ago
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    ohhh yea should be fun

  62. dan815
    • one year ago
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    we did some PDE toward the end of this year but i dont think its like indepth as ur PDE class

  63. FibonacciChick666
    • one year ago
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    yep haha and in the fall i have abstract algebra, ODE, topology or something (math elective) ASL 3 uhmmmand something else haha

  64. FibonacciChick666
    • one year ago
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    and prob not this class is going to suck massively

  65. dan815
    • one year ago
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    its gonna be like that Heat equation wave equation and laplace right then using fourier series to solve?

  66. dan815
    • one year ago
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    thats as far as we got, just doing simple boundary value problems with that

  67. FibonacciChick666
    • one year ago
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    ... were you following me on here tonight? lol

  68. dan815
    • one year ago
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    whaatt do u mean

  69. FibonacciChick666
    • one year ago
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    i just answered a PDE on here earlier lol

  70. dan815
    • one year ago
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    oh haha

  71. dan815
    • one year ago
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    i just had to cram all that stuff for my exam a couple days ago T_T

  72. FibonacciChick666
    • one year ago
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    yucky

  73. dan815
    • one year ago
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    it was a feather trying to learn fourier series and PDE in 2 days, I was actually gonna give up on the exam.. i went to my mom and was like NO MORE!! I WILL take this in summer

  74. dan815
    • one year ago
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    but she gave me this huge LECTURE ON stick it out, just believe GOD

  75. FibonacciChick666
    • one year ago
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    I had linear algebra personally but that sounds dreadful which class?

  76. FibonacciChick666
    • one year ago
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    ...math gods?

  77. dan815
    • one year ago
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    lol

  78. FibonacciChick666
    • one year ago
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    I know I usually pray to bolzano or laplace hbu? haha

  79. dan815
    • one year ago
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    lmao, just Jesus for me :)

  80. FibonacciChick666
    • one year ago
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    ok if that works for ya haha

  81. dan815
    • one year ago
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    it dooess!! we seen too much to not believe in god

  82. dan815
    • one year ago
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    i actually used to be a drug addict and stuff, till I heard God, and my addictions everything even coffee addiction i dunno how lol, just went away over night

  83. dan815
    • one year ago
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    like my addictions were really really bad, i cudnt control it i cudnt get throught out a day if i wasnt high, not even 5 - 10 mins xD

  84. FibonacciChick666
    • one year ago
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    thats cool for you and i'm happy you are no longer an addict

  85. dan815
    • one year ago
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    yep :)

  86. FibonacciChick666
    • one year ago
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    i am still a firm believer in skepticism however

  87. dan815
    • one year ago
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    haha thats fine, i wud have never believed it till it finally happened to me

  88. FibonacciChick666
    • one year ago
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    I was raised wayyyy too catholic, then I started thinking on my own and yep. that is how i am where i am now

  89. dan815
    • one year ago
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    thats cool

  90. FibonacciChick666
    • one year ago
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    but oh well, differences aside i think i'm heading to sleep/work so i'll talk to ya again soon and I'll answer this later today when I've slept a little haha

  91. dan815
    • one year ago
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    okay good night sleep well :)

  92. FibonacciChick666
    • one year ago
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    Night! and you too!

  93. dan815
    • one year ago
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    love you lol..

  94. dan815
    • one year ago
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    saying good night is a very touchy time i feel

  95. NadiaKamal
    • one year ago
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    HEY THIS IS THE RIGHT ANSWER

  96. NadiaKamal
    • one year ago
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    he probability of getting 5 heads in 10 tosses =10C5(1/2^5)(1/2^5)=252/1024=0.2461.SIMILARLY the probability of not getting five heads=1-0.2461=0.7539. now the probability of three students not getting 5 heads =(0.7539)^3=0.4285 so at last the probability of atleast one student get exactly five heads =1-0.4285 which is 0.5715

  97. dan815
    • one year ago
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    @NadiaKamal :)

  98. dan815
    • one year ago
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    |dw:1367222891831:dw|

  99. dan815
    • one year ago
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    |dw:1367222963861:dw|

  100. dan815
    • one year ago
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    that is the probability for 1 TA getting 5 outta 10 flips as heads so for atleast 1, or otherwise, inpreted as when none of the TAs get 5 outta 10 = 1-(10 choose 5/2^10) ^3= prob of all 3 TA not getting 5 in a row so 1- prob of all 3 TA not getting 5 in a row = answer

  101. KABRIC
    • one year ago
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    THX

  102. KABRIC
    • one year ago
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    BOTH NADIA AND DAN THX

  103. dan815
    • one year ago
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    YW:)

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