Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Separation of variables, Schrodinger's Equation. For the first part of a physics homework question, I am given an equation and am told to separate the variables in a certain way. I am pretty sure this is part of ordinary differential equations, which I have never learned. (Not a pre- or co-requisite of my course.) Here is what I am asked - any help would be appreciated! Thank you! The Schrodinger equation for two dimensions is \[(\frac{\delta ^2}{\delta x^2} \frac{\delta ^2}{\delta y^2}) \psi (x,y) = - \frac{2m(E-U)}{\hbar ^2} \psi (x,y)\] U is constant. I am supposed to "separate variables by trying a solution of the form \[\psi (x,y) = f(x) g(y)\] then dividing by \[f(x) g(y)\]." It also says to call the separation constants \[C_x \]and\[ C_y\]

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
I'm sorry I'm a bit rusty on def eq, maybe Paul's could help? http://tutorial.math.lamar.edu/Classes/CalcIII/CalcIII.aspx He has a dif eq page
Thank you for looking at it! :) I'll check it out!
Np, and you can always look at khan academy They might have something on Schrodinger's

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Thank you for your help! Let's see how fast I can learn this stuff!
haha quantum mechanics?
http://www.khanacademy.org/math/differential-equations/first-order-differential-equations/differential-equations-intro/v/what-is-a-differential-equation I didn't watch it but I think this is your problem :)
Yep! Or at least this ODE stuff! I mean, can't be that hard.. Quantum Mechanics... The course is on wave-particle theory... I think they should include more math as a prerequisite! Calc 3 is the only math corequisite. I guess it would make the degree take a lot longer to get, though, if ODE was required.. Back to work, now!....
Thank you for all your help!
And have a good night! :)
woww... ok well now that I'm curious if I get it I'll post it. Good luck, and good night!
Haha, okay! Please don't tax yourself for my sake!
nah I have PDE over the summer so it should be a good review. ODE is in the fall too so I should practice :)
I see! God luck in both! I'll be taking ODE in the fall, but reading about it over the summer!
I apologize if this problem does end up involving physics!
meh it might but it's still fun for a nerd like me
ok need more info, do you know the values for m, E, and h bar?
Constant... h bar is 1.055*10^-34 [some units]. I imagine that they should stay in the equations, too, to be exact. I'm sorry I didn't say that they're all constant! That is a physics part... My bad! :\ The book didn't specify in the question, because it's taken for granted in a physics context.
ahh then it's not bad I'm going to simplify that fraction to P ok?
Watching Khan Academy's video you sent me, the "solution" thing makes so much more sense! I need to use ODE stuff to find \[\psi(x,y)\]and it should then, somehow, be expressed as a function of x multiplied by a function of y. The "P" thing is fine with me!
well it's actually a PDE, due to the partials give me a few more minutes and I'll have it(hopefully)
Thank you! It doesn't hurt if you don't get it - so no pressure! You've already helped so much!
http://www.math.umn.edu/~olver/pd_/sv.pdf p 123 should help
I think it's in Greek though. Just kidding.... Thank you! I'll read more than the first sentence now...
p 122 at the bottom
It is almost exactly your problem :)
Thank you! Very much! I'll continue to look at it. I added it to my favorites, too. If you ever need help with something I might know, tag me if you want a hand. I owe you. I don't get on Open Study much because I have been very busy with my own work, but at least my e-mail will have a notification. I don't know how much help I could, be, but I can try.
Np and your welcome, I hate physics so hopefully I can avoid it, but at least now I know who to call for help ;) If you need any Calc 3 or upper math help you can still ask me, I should be at grad student level this time next year (fingers crossed) and random questions like this are good practice. Good luck with finals!
Cool, good luck! Yeah, if they stick you in a physics course for fun, I'll do my best to help! :)
b) For an infinite well,\[U=\left(\begin{matrix} 0 & 0
c) How many independent quantum numbers are there? d) Find the allowed energies E. e) Are there energies for which there is not a unique corresponding wave function?
thanks!!
Not a problem! Enjoy! If possible! :P
haha i am sure i will
That's scary. Kidding!
I think the solution was:\[\frac{\delta ^2 f(x)}{f(x) \delta x^2}+\frac{\delta ^2 g(y)}{g(y) \delta y^2}=-\frac{2m(E-U)}{\hbar ^2}\] I Think that was it... And \[\frac{\delta ^2 f(x)}{f(x) \delta x^2}=C_x\]\[\frac{\delta ^2 g(y)}{g(y) \delta y^2}=C_y\]since the two terms are independent and add up to be a constant.
I'll ask a few people I know who are really good at this cause it's bothering me lol
Maybe it was physics-related! I know that separation of variables is an ODE procedure and is very helpful in physics, though!
lol did you at least get the answer?
I think that my post from 3 days ago is the answer. I based it on some other math in the textbook that I didn't understand. It was a similar process, in the book.
hmm ok well good luck with finals!
and you can bet I'll be hitting you up for physics help in the future
Also on second look and seeing that the end result is a constant, i agree with your answer
Sounds good! I like Open Study, so I should be on every once in a while! And I'll have more free time next semester. I'll be on in the summer, too. Yeah! The two terms on the left must be constant because the terms are independent of each other and they add up to a constant! I learned that. And it makes sense, where independent here means that a change in the left term will not affect the value of the right term, which must be added to the left term to arrive at a constant.
I'll be here too and yea i kept forgetting that that big fraction was a constant lol
Yeah, tougher when it's less native to you!! Good luck in PDE! I'll be reading a book from Amazon to learn ODE so it's not as bad in the fall.

Not the answer you are looking for?

Search for more explanations.

Ask your own question