DLS
  • DLS
Test whether the following function is odd/even/either/neither
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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DLS
  • DLS
\[f(x)=\sin(\log(x-\sqrt{x^2+1}))\]
DLS
  • DLS
\[f(-x)=\sin(\log(\sqrt{x^2+1}-x)) \]
hartnn
  • hartnn
log (-A) is not -log A or log A so, its neither.

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More answers

DLS
  • DLS
its odd...
hartnn
  • hartnn
lets try an simplify x= tan y
DLS
  • DLS
@yrelhan4
yrelhan4
  • yrelhan4
rationalize..
DLS
  • DLS
kyun?
yrelhan4
  • yrelhan4
just rationalize f(-x).. you'll get to know why.
DLS
  • DLS
kyun karna hai?kaise pata chalega?
yrelhan4
  • yrelhan4
ye rd ka question hai. to mereko pta hai.. :P
hartnn
  • hartnn
you'll be using log (1/A) = - log A property here.
hartnn
  • hartnn
an sin(-t) = - sin t
DLS
  • DLS
ye to IIT ques hai..and why cant i see anyone viewing this question?
DLS
  • DLS
u cant either?
DLS
  • DLS
if I rationalize then how i am I using 1/logA property?
DLS
  • DLS
okay now i can see
DLS
  • DLS
people viewing
yrelhan4
  • yrelhan4
:/
hartnn
  • hartnn
what u got after rationalizing ?
DLS
  • DLS
\[\large x-\sqrt{x^2+1} \times \frac{x+\sqrt{x^2+1}}{{x+\sqrt{x^2+1}}}=\frac{1}{\sqrt{x^2+1}}\] hmm but how am i gonna think of this ?
DLS
  • DLS
misprint in = sorry :|
yrelhan4
  • yrelhan4
iit ka question hai mere bhai..
DLS
  • DLS
x+ also there
DLS
  • DLS
still :|
DLS
  • DLS
okay i have another doubt
DLS
  • DLS
\[\large \frac{1}{x+\sqrt{x^2+1}}\] =logA? logA to 1/x-sqrt{x^2+1} tha..minus tha :|
yrelhan4
  • yrelhan4
nhi.. galat hai method. pta nhi. :/
yrelhan4
  • yrelhan4
@hartnn ? :O
hartnn
  • hartnn
what ?
yrelhan4
  • yrelhan4
dls's last post. rationalizing wont work.
hartnn
  • hartnn
it does ?
hartnn
  • hartnn
rationalizing changes middle sign :\]
yrelhan4
  • yrelhan4
we'll get log(x+ sqrt(x^2+1)) right? but f(x) is..... exactly...
DLS
  • DLS
dafuq :|
DLS
  • DLS
@yrelhan4 RD khol
yrelhan4
  • yrelhan4
yr dusre room me padi hai. :/
DLS
  • DLS
ja na please :| mere solution me usse (a+b)(a-b) ka use kara hai..why :/
DLS
  • DLS
\[\LARGE \sin(\log(\frac{1}{x+\sqrt{x^2+1}}))=\sin(\log1-\log(x+\sqrt{x^2+1}\] ..done

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