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DLS

  • 2 years ago

Test whether the following function is odd/even/either/neither

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  1. DLS
    • 2 years ago
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    \[f(x)=\sin(\log(x-\sqrt{x^2+1}))\]

  2. DLS
    • 2 years ago
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    \[f(-x)=\sin(\log(\sqrt{x^2+1}-x)) \]

  3. hartnn
    • 2 years ago
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    log (-A) is not -log A or log A so, its neither.

  4. DLS
    • 2 years ago
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    its odd...

  5. hartnn
    • 2 years ago
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    lets try an simplify x= tan y

  6. DLS
    • 2 years ago
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    @yrelhan4

  7. yrelhan4
    • 2 years ago
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    rationalize..

  8. DLS
    • 2 years ago
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    kyun?

  9. yrelhan4
    • 2 years ago
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    just rationalize f(-x).. you'll get to know why.

  10. DLS
    • 2 years ago
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    kyun karna hai?kaise pata chalega?

  11. yrelhan4
    • 2 years ago
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    ye rd ka question hai. to mereko pta hai.. :P

  12. hartnn
    • 2 years ago
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    you'll be using log (1/A) = - log A property here.

  13. hartnn
    • 2 years ago
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    an sin(-t) = - sin t

  14. DLS
    • 2 years ago
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    ye to IIT ques hai..and why cant i see anyone viewing this question?

  15. DLS
    • 2 years ago
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    u cant either?

  16. DLS
    • 2 years ago
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    if I rationalize then how i am I using 1/logA property?

  17. DLS
    • 2 years ago
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    okay now i can see

  18. DLS
    • 2 years ago
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    people viewing

  19. yrelhan4
    • 2 years ago
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    :/

  20. hartnn
    • 2 years ago
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    what u got after rationalizing ?

  21. DLS
    • 2 years ago
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    \[\large x-\sqrt{x^2+1} \times \frac{x+\sqrt{x^2+1}}{{x+\sqrt{x^2+1}}}=\frac{1}{\sqrt{x^2+1}}\] hmm but how am i gonna think of this ?

  22. DLS
    • 2 years ago
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    misprint in = sorry :|

  23. yrelhan4
    • 2 years ago
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    iit ka question hai mere bhai..

  24. DLS
    • 2 years ago
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    x+ also there

  25. DLS
    • 2 years ago
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    still :|

  26. DLS
    • 2 years ago
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    okay i have another doubt

  27. DLS
    • 2 years ago
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    \[\large \frac{1}{x+\sqrt{x^2+1}}\] =logA? logA to 1/x-sqrt{x^2+1} tha..minus tha :|

  28. yrelhan4
    • 2 years ago
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    nhi.. galat hai method. pta nhi. :/

  29. yrelhan4
    • 2 years ago
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    @hartnn ? :O

  30. hartnn
    • 2 years ago
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    what ?

  31. yrelhan4
    • 2 years ago
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    dls's last post. rationalizing wont work.

  32. hartnn
    • 2 years ago
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    it does ?

  33. hartnn
    • 2 years ago
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    rationalizing changes middle sign :\]

  34. yrelhan4
    • 2 years ago
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    we'll get log(x+ sqrt(x^2+1)) right? but f(x) is..... exactly...

  35. DLS
    • 2 years ago
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    dafuq :|

  36. DLS
    • 2 years ago
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    @yrelhan4 RD khol

  37. yrelhan4
    • 2 years ago
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    yr dusre room me padi hai. :/

  38. DLS
    • 2 years ago
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    ja na please :| mere solution me usse (a+b)(a-b) ka use kara hai..why :/

  39. DLS
    • 2 years ago
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    \[\LARGE \sin(\log(\frac{1}{x+\sqrt{x^2+1}}))=\sin(\log1-\log(x+\sqrt{x^2+1}\] ..done

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