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locitalovesu

  • one year ago

Please help!! The vertices of a triangle are A(16, 0), B(9, 2), and C(0, 0). Which side is also an altitude with a slope of -2/7? side AB side BC side AC

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  1. nickersia
    • one year ago
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    AB Need explanation?

  2. locitalovesu
    • one year ago
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    yes please

  3. nickersia
    • one year ago
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    Try to draw a diagram roughly, points A and C are on the x axis. So from C to B the line will go up (positive slope), and from B to A the line will go down (negative slope). Does that makes any sense? :)

  4. locitalovesu
    • one year ago
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    Yupp

  5. surjithayer
    • one year ago
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    |dw:1367265570052:dw|

  6. surjithayer
    • one year ago
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    slope of AB=(2-0)/(9-16)=-2/7 AB=sqrt[(9-16)^2+(2-0)^2]=sqrt(49+4)=sqrt53 BC=sqrt[(0-9)^2+(0-2)^2]=sqrt85 AC=sqrt [(0-16)^2+(0-0)^2]=16 neither AC^2=BC^2+AB^2,Because 53+85=138 not =to 256 nor BC^2=AC^2+AB^2,Because 256+53=309 not= to 85 AB is not an altitude of triangle ABC though it has slope -2/7

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