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anonymous
 3 years ago
A lumberjack has 4n + 110 logs in a pile consisting of n layers. Each layer has two more logs than the layer directly above it. If the top layer has six logs, how many layers are there? Write the steps to calculate the equation for the problem and state the number of layers.
anonymous
 3 years ago
A lumberjack has 4n + 110 logs in a pile consisting of n layers. Each layer has two more logs than the layer directly above it. If the top layer has six logs, how many layers are there? Write the steps to calculate the equation for the problem and state the number of layers.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So for the topmost layer you have 6 logs, then you have 8, then 10 etc. 6 + (6+2) + (6+2+2)+...+(6+2(n1)) = 4n + 110. You have to find the sum of an arithmetic sequence with first term 6 and common difference 2 with n terms. First term: 6, Last term: 2n+4. Then substitute Sum of sequence = 4n+110 and solve for n.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay this would be 4 divided by 110?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry, what is 25n? Sum of sequence or?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm really not sure how to do this

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, so how would you find the sum of an arithmetic series? Say, if I told you the first term was 6, the last was 14, and the common difference was 2. (6 + 8 + 10 + 12 + 14.) Apart from adding them up one by one.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Since the terms increased by the same amount each time, you could take the average and multiply it by the number of terms. The average would be (first term + last term)/2.
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