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austinL
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At a certain time a particle had a speed of 80 m/s in the positive x direction, and 7.0 s later its speed was 90 m/s in the opposite direction. What was the average acceleration of the particle during this 7.0 s interval?
I can think of two answers that I could get:
24.29m/s^2
1.43 m/s^2
Any help would be appreciated.
 one year ago
 one year ago
austinL Group Title
At a certain time a particle had a speed of 80 m/s in the positive x direction, and 7.0 s later its speed was 90 m/s in the opposite direction. What was the average acceleration of the particle during this 7.0 s interval? I can think of two answers that I could get: 24.29m/s^2 1.43 m/s^2 Any help would be appreciated.
 one year ago
 one year ago

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MarcLeclair Group TitleBest ResponseYou've already chosen the best response.1
I got 24.29 too but I haven't done these kind of problems in a long time. I just looked at the change of speed ( so from 80 to 0 and 0 to 90 considering it is in the opposite direction). So I put the acceleration as 24.28. ^^ ( well a = speed / delta t
 one year ago

MarcLeclair Group TitleBest ResponseYou've already chosen the best response.1
or if you want to spend the time on it, draw the graph, find the rule of the velocity graph ( should be a linear one ax+b) and integrate it ^^
 one year ago

austinL Group TitleBest ResponseYou've already chosen the best response.0
Ok, thanks! I just wanted another set of eyes to look at it.
 one year ago
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