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Nick_PBest ResponseYou've already chosen the best response.0
never mind just 4 sorry :P
 11 months ago

dustyBest ResponseYou've already chosen the best response.1
this is for number 4 http://www.wolframalpha.com/input/?i=2x%5E2%2B6x+over+10x%5E3
 11 months ago

Nick_PBest ResponseYou've already chosen the best response.0
ok yea thats not the same prob i just need to kno like can u show ur work on how its done?
 11 months ago

dustyBest ResponseYou've already chosen the best response.1
yah give me a min im figuring it out right now(:
 11 months ago

dustyBest ResponseYou've already chosen the best response.1
(2x2+6x)(10x3) To simplify this we need to cancel the common factors from the numerator and the denominator We see that 2x is common in both terms of numerator (2x×x+3×2x.)(10x3) and 2x is also a factor of the denominator (2x×x+3×2x.)(2x×5x2) Now you cancel 2x from both numerator and denominator!!
 11 months ago

dustyBest ResponseYou've already chosen the best response.1
i did this stuff last night when i was studying for my eoc and did a problem just like this lol
 11 months ago
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