Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Nick_P

  • 3 years ago

Can someone help me!

  • This Question is Closed
  1. Nick_P
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    4 and 6

    1 Attachment
  2. Nick_P
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    never mind just 4 sorry :P

  3. dusty
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    this is for number 4 http://www.wolframalpha.com/input/?i=2x%5E2%2B6x+over+10x%5E3

  4. Nick_P
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok yea thats not the same prob i just need to kno like can u show ur work on how its done?

  5. dusty
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yah give me a min im figuring it out right now(:

  6. Nick_P
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    k

  7. dusty
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    (2x2+6x)(10x3) To simplify this we need to cancel the common factors from the numerator and the denominator We see that 2x is common in both terms of numerator (2x×x+3×2x.)(10x3) and 2x is also a factor of the denominator (2x×x+3×2x.)(2x×5x2) Now you cancel 2x from both numerator and denominator!!

  8. Nick_P
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thx

  9. dusty
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ur very welcome(:

  10. dusty
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i did this stuff last night when i was studying for my eoc and did a problem just like this lol

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy