Here's the question you clicked on:
Nick_P
Can someone help me!
never mind just 4 sorry :P
this is for number 4 http://www.wolframalpha.com/input/?i=2x%5E2%2B6x+over+10x%5E3
ok yea thats not the same prob i just need to kno like can u show ur work on how its done?
yah give me a min im figuring it out right now(:
(2x2+6x)(10x3) To simplify this we need to cancel the common factors from the numerator and the denominator We see that 2x is common in both terms of numerator (2x×x+3×2x.)(10x3) and 2x is also a factor of the denominator (2x×x+3×2x.)(2x×5x2) Now you cancel 2x from both numerator and denominator!!
i did this stuff last night when i was studying for my eoc and did a problem just like this lol