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anonymous
 3 years ago
Can someone help me!!!
anonymous
 3 years ago
Can someone help me!!!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(2a^24a+2) / (3a^23) 2(a^22a+1) / 3(a^21) 2(a1)(a1) / 3(a+1)(a1) 2(a1) / 3(a+1) You can leave it at that. Or write it out as (2a2) / (3a+3). I would just leave it factored though

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i only saw the number 7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im not to sure on these but @mathstudent55 do you think you could help him?

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.17. is correct. Good job @dusty

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but im not for sure on 8 & 9

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.18. (2s^2  5s  12) / (2s^2  9s + 4) The basic idea is the same as for 7. First factor the numerator and denominator.

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1You need to factor 2s^2  5s  12 This is a trinomial of the form ax^2 + bx + c To factor do the following: 1. First try to factor a common factor from all terms, if there is one. In this case there isn't a common factor.

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.12. Multiply ac together. In this case, a = 2, and c = 12, so ac = 2(12) = 24

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.13. Come up with two dfactors of ac that add up to b. In this case, we need two factors of 24 that add up to 5. Since 8*3 = 24, 8*3 = 24, and 8 + 3 = 5, so the factors are 8 and 3.

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.14. Now break up the middle term of the trinomial, bx, into a sum of the factors from step 3. In this case, 5s becomes 8s + 3s. 5. Rewrite the trinomial using the new brokenup middle term. In this case, 2s^2  8s + 3s  12

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.16. Now factor by parts. That means, factor a common factor out of the first two terms, and factor a common factor out of the last two terms. In this case, 2s^2  8s + 3s  12 = 2s(s  4) + 3(s  4) 7. Pull out the common factor to complete the factoring. In this case, 2s(s  4) + 3(s  4) = (s  4)(2s + 3)

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1Now you need to do the same to teh denominator. You need to factor 2s^2  9s + 4 If you follow the steps above, youi'll get: (2s  1)(s  4)

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1Now that both the numerator and the denominator are factored, you have: (2s^2  5s  12) / (2s^2  9s + 4) = [ (s  4)(2s + 3) ] / [ (2s  1)(s  4) ] Notice that s  4 is in both the numerator and denominator, so you can divide both the numerator and denominator by s  4: (2s + 3) / (2s  1)

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1That's the final answer of 8. For 9, you once again have to factor the numerator and denominator if possible. This happens to be a very simple problem of this type because the factoring involved is very easy.
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