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walter9906

  • 3 years ago

Find cos 2A, Sin A = -2/9

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  1. genius12
    • 3 years ago
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    You will need to use some identities here:\[\bf \cos(2a)=1-2\sin^2(a)\]We know what sin(a) is, so we just plug that in to the identity and evaluate.\[\bf \cos(2a)=1-2(-2/9)^2=..?\]Can you evaluate that? @walter9906

  2. walter9906
    • 3 years ago
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    Thank you. I have one more. find Cos 2A \[\cos A=\sqrt{3}/4\]

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