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Can someone PLEASE explain how to solve this? The fraction at the end completely throws me off!!
Pic related: http://prntscr.com/12xgei
 11 months ago
 11 months ago
Can someone PLEASE explain how to solve this? The fraction at the end completely throws me off!! Pic related: http://prntscr.com/12xgei
 11 months ago
 11 months ago

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terenzreignzBest ResponseYou've already chosen the best response.2
Okay... So, essentially \[\huge \frac{f}g(x) = \frac{f(x)}{g(x)}\] is the key to understanding this...
 11 months ago

SephIBest ResponseYou've already chosen the best response.1
I deducted it and f(x) = 3 and g(x) = 7 But, my answer isn't 7... My answers are: 3 3 1 1 I tried dividing 3 by 7 and 7 by 3, but that didn't work.
 11 months ago

terenzreignzBest ResponseYou've already chosen the best response.2
f(x) = 3? I take it you meant f(2) indeed, f(2) = 3 I suggest you retry g(2)
 11 months ago

SephIBest ResponseYou've already chosen the best response.1
I thought: \[\frac{ f }{ g }(2) = \frac{ f(2) }{ g }\] Then I'd find f(2) Then I'd plug in 2 to g(x) and get 7.
 11 months ago

terenzreignzBest ResponseYou've already chosen the best response.2
Ahh. No. \[\huge \frac{f}g(x) = \frac{f(x)}{g(x)}\\\huge \frac{f}g(2)=\frac{f(2)}{g(2)}\]
 11 months ago

terenzreignzBest ResponseYou've already chosen the best response.2
It does bug me when they use shorthand notation resulting into unclear stuff... but yeah, that's Maths for you :P
 11 months ago

SephIBest ResponseYou've already chosen the best response.1
Here is what I did: f(x) = 3x  3 f(x) = 3(2)  3 f(x) = 6  3 f(x) = 3 Plug it into g g(x) = 2(3) + 1 g(x) = 7 But the answer isn't seven. Am I doing it wrong?
 11 months ago

terenzreignzBest ResponseYou've already chosen the best response.2
because you're not supposed to get g(f(2)) Just g(2)
 11 months ago

SephIBest ResponseYou've already chosen the best response.1
\[\frac{ 3(2)  3 }{ 2(2) + 1 }\] Is that it?
 11 months ago

SephIBest ResponseYou've already chosen the best response.1
\[\frac{ 3 }{ 3 } = 1\]
 11 months ago

SephIBest ResponseYou've already chosen the best response.1
Okay, and can you explain the g(f[4]) thingy?
 11 months ago

terenzreignzBest ResponseYou've already chosen the best response.2
That's when you first get the result of f(4) and then plug it into g(x)
 11 months ago

SephIBest ResponseYou've already chosen the best response.1
And if you had f(g[4]) You'd first get g and plug it into f?
 11 months ago

terenzreignzBest ResponseYou've already chosen the best response.2
You'd first get g(4) and then plug it into f(x) , yes :)
 11 months ago

SephIBest ResponseYou've already chosen the best response.1
I see. It's all about order. But sometimes it's so unclear ;;
 11 months ago

terenzreignzBest ResponseYou've already chosen the best response.2
Hopefully clearer now, if only a little bit :)
 11 months ago
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