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anonymous
 3 years ago
Can someone PLEASE explain how to solve this? The fraction at the end completely throws me off!!
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anonymous
 3 years ago
Can someone PLEASE explain how to solve this? The fraction at the end completely throws me off!! Pic related: http://prntscr.com/12xgei

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terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2Okay... So, essentially \[\huge \frac{f}g(x) = \frac{f(x)}{g(x)}\] is the key to understanding this...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I deducted it and f(x) = 3 and g(x) = 7 But, my answer isn't 7... My answers are: 3 3 1 1 I tried dividing 3 by 7 and 7 by 3, but that didn't work.

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2f(x) = 3? I take it you meant f(2) indeed, f(2) = 3 I suggest you retry g(2)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I thought: \[\frac{ f }{ g }(2) = \frac{ f(2) }{ g }\] Then I'd find f(2) Then I'd plug in 2 to g(x) and get 7.

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2Ahh. No. \[\huge \frac{f}g(x) = \frac{f(x)}{g(x)}\\\huge \frac{f}g(2)=\frac{f(2)}{g(2)}\]

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2It does bug me when they use shorthand notation resulting into unclear stuff... but yeah, that's Maths for you :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Here is what I did: f(x) = 3x  3 f(x) = 3(2)  3 f(x) = 6  3 f(x) = 3 Plug it into g g(x) = 2(3) + 1 g(x) = 7 But the answer isn't seven. Am I doing it wrong?

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2because you're not supposed to get g(f(2)) Just g(2)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 3(2)  3 }{ 2(2) + 1 }\] Is that it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 3 }{ 3 } = 1\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, and can you explain the g(f[4]) thingy?

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2That's when you first get the result of f(4) and then plug it into g(x)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And if you had f(g[4]) You'd first get g and plug it into f?

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2You'd first get g(4) and then plug it into f(x) , yes :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I see. It's all about order. But sometimes it's so unclear ;;

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2Hopefully clearer now, if only a little bit :)
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