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Venomblast

  • one year ago

put this in polar form 5-12i

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  1. Venomblast
    • one year ago
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    i got r=13

  2. Venomblast
    • one year ago
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    I do not want my answers in degree

  3. Venomblast
    • one year ago
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    basically what i need help is converting my answer to degree to rad in decimal

  4. terenzreignz
    • one year ago
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    So you already have your angle in degrees?

  5. Venomblast
    • one year ago
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    292.61 degree.

  6. terenzreignz
    • one year ago
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    In that case, if you have it in degrees, to bring it to radians, simply multiply it by the factor \[\huge \frac{\pi}{180^o}\]

  7. Venomblast
    • one year ago
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    |dw:1367393591344:dw|

  8. agent0smith
    • one year ago
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    |dw:1367393361730:dw| for a number a+bi \[\large r^2 = a^2 + b^2\] tan theta = \[\large \tan \theta = \frac{ b }{a }\] To convert from degrees to radians \[\Large \theta ^{r} = \theta ^{d} \times \frac{ \pi }{180}\] theta d means theta in degrees.

  9. Venomblast
    • one year ago
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    hey one more question. if 5 was negative would it still be \[\tan \theta b/a\] or will the a be negative?

  10. agent0smith
    • one year ago
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    Like this? |dw:1367393943561:dw| \[\tan \theta = \frac{ -12 }{-5 }\] which gives theta = 67.4 degrees or 1.18 radians... BUT as you can see, theta is in the third quadrant, so you need to add 180 degrees to 67.4 degrees, or add pi radians to 1.18 radians... giving 247.4 degrees or 4.31 radians. This is why drawing a diagram is helpful.

  11. Venomblast
    • one year ago
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    no what I am trying to say is, does it matter of a or b is positive or negative or do you just take the absolute value of 12 and 5 when figuring out tan theta

  12. agent0smith
    • one year ago
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    Oh, no, you use b and a exactly as they are, you can take the abs value, but that just means more work to find the actual angle.

  13. agent0smith
    • one year ago
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    Because tan is negative in the 2nd and fourth quadrants, so it's helpful to keep the negatives as they are: http://upload.wikimedia.org/wikipedia/commons/thumb/a/a7/All_Students_Take_Calculus.svg/220px-All_Students_Take_Calculus.svg.png

  14. Venomblast
    • one year ago
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    i tan is always positive if you take the abs of a and b

  15. agent0smith
    • one year ago
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    Eh? we don't want tan to always be positive... there's no need for that. Keeping the negatives can actually save you some work...

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