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Venomblast Group Title

put this in polar form 5-12i

  • one year ago
  • one year ago

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  1. Venomblast Group Title
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    i got r=13

    • one year ago
  2. Venomblast Group Title
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    I do not want my answers in degree

    • one year ago
  3. Venomblast Group Title
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    basically what i need help is converting my answer to degree to rad in decimal

    • one year ago
  4. terenzreignz Group Title
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    So you already have your angle in degrees?

    • one year ago
  5. Venomblast Group Title
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    292.61 degree.

    • one year ago
  6. terenzreignz Group Title
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    In that case, if you have it in degrees, to bring it to radians, simply multiply it by the factor \[\huge \frac{\pi}{180^o}\]

    • one year ago
  7. Venomblast Group Title
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    |dw:1367393591344:dw|

    • one year ago
  8. agent0smith Group Title
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    |dw:1367393361730:dw| for a number a+bi \[\large r^2 = a^2 + b^2\] tan theta = \[\large \tan \theta = \frac{ b }{a }\] To convert from degrees to radians \[\Large \theta ^{r} = \theta ^{d} \times \frac{ \pi }{180}\] theta d means theta in degrees.

    • one year ago
  9. Venomblast Group Title
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    hey one more question. if 5 was negative would it still be \[\tan \theta b/a\] or will the a be negative?

    • one year ago
  10. agent0smith Group Title
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    Like this? |dw:1367393943561:dw| \[\tan \theta = \frac{ -12 }{-5 }\] which gives theta = 67.4 degrees or 1.18 radians... BUT as you can see, theta is in the third quadrant, so you need to add 180 degrees to 67.4 degrees, or add pi radians to 1.18 radians... giving 247.4 degrees or 4.31 radians. This is why drawing a diagram is helpful.

    • one year ago
  11. Venomblast Group Title
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    no what I am trying to say is, does it matter of a or b is positive or negative or do you just take the absolute value of 12 and 5 when figuring out tan theta

    • one year ago
  12. agent0smith Group Title
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    Oh, no, you use b and a exactly as they are, you can take the abs value, but that just means more work to find the actual angle.

    • one year ago
  13. agent0smith Group Title
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    Because tan is negative in the 2nd and fourth quadrants, so it's helpful to keep the negatives as they are: http://upload.wikimedia.org/wikipedia/commons/thumb/a/a7/All_Students_Take_Calculus.svg/220px-All_Students_Take_Calculus.svg.png

    • one year ago
  14. Venomblast Group Title
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    i tan is always positive if you take the abs of a and b

    • one year ago
  15. agent0smith Group Title
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    Eh? we don't want tan to always be positive... there's no need for that. Keeping the negatives can actually save you some work...

    • one year ago
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