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Venomblast
put this in polar form 5-12i
I do not want my answers in degree
basically what i need help is converting my answer to degree to rad in decimal
So you already have your angle in degrees?
In that case, if you have it in degrees, to bring it to radians, simply multiply it by the factor \[\huge \frac{\pi}{180^o}\]
|dw:1367393591344:dw|
|dw:1367393361730:dw| for a number a+bi \[\large r^2 = a^2 + b^2\] tan theta = \[\large \tan \theta = \frac{ b }{a }\] To convert from degrees to radians \[\Large \theta ^{r} = \theta ^{d} \times \frac{ \pi }{180}\] theta d means theta in degrees.
hey one more question. if 5 was negative would it still be \[\tan \theta b/a\] or will the a be negative?
Like this? |dw:1367393943561:dw| \[\tan \theta = \frac{ -12 }{-5 }\] which gives theta = 67.4 degrees or 1.18 radians... BUT as you can see, theta is in the third quadrant, so you need to add 180 degrees to 67.4 degrees, or add pi radians to 1.18 radians... giving 247.4 degrees or 4.31 radians. This is why drawing a diagram is helpful.
no what I am trying to say is, does it matter of a or b is positive or negative or do you just take the absolute value of 12 and 5 when figuring out tan theta
Oh, no, you use b and a exactly as they are, you can take the abs value, but that just means more work to find the actual angle.
Because tan is negative in the 2nd and fourth quadrants, so it's helpful to keep the negatives as they are: http://upload.wikimedia.org/wikipedia/commons/thumb/a/a7/All_Students_Take_Calculus.svg/220px-All_Students_Take_Calculus.svg.png
i tan is always positive if you take the abs of a and b
Eh? we don't want tan to always be positive... there's no need for that. Keeping the negatives can actually save you some work...