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Venomblast
 one year ago
put this in polar form 512i
Venomblast
 one year ago
put this in polar form 512i

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Venomblast
 one year ago
Best ResponseYou've already chosen the best response.1I do not want my answers in degree

Venomblast
 one year ago
Best ResponseYou've already chosen the best response.1basically what i need help is converting my answer to degree to rad in decimal

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1So you already have your angle in degrees?

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.1In that case, if you have it in degrees, to bring it to radians, simply multiply it by the factor \[\huge \frac{\pi}{180^o}\]

Venomblast
 one year ago
Best ResponseYou've already chosen the best response.1dw:1367393591344:dw

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2dw:1367393361730:dw for a number a+bi \[\large r^2 = a^2 + b^2\] tan theta = \[\large \tan \theta = \frac{ b }{a }\] To convert from degrees to radians \[\Large \theta ^{r} = \theta ^{d} \times \frac{ \pi }{180}\] theta d means theta in degrees.

Venomblast
 one year ago
Best ResponseYou've already chosen the best response.1hey one more question. if 5 was negative would it still be \[\tan \theta b/a\] or will the a be negative?

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2Like this? dw:1367393943561:dw \[\tan \theta = \frac{ 12 }{5 }\] which gives theta = 67.4 degrees or 1.18 radians... BUT as you can see, theta is in the third quadrant, so you need to add 180 degrees to 67.4 degrees, or add pi radians to 1.18 radians... giving 247.4 degrees or 4.31 radians. This is why drawing a diagram is helpful.

Venomblast
 one year ago
Best ResponseYou've already chosen the best response.1no what I am trying to say is, does it matter of a or b is positive or negative or do you just take the absolute value of 12 and 5 when figuring out tan theta

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2Oh, no, you use b and a exactly as they are, you can take the abs value, but that just means more work to find the actual angle.

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2Because tan is negative in the 2nd and fourth quadrants, so it's helpful to keep the negatives as they are: http://upload.wikimedia.org/wikipedia/commons/thumb/a/a7/All_Students_Take_Calculus.svg/220pxAll_Students_Take_Calculus.svg.png

Venomblast
 one year ago
Best ResponseYou've already chosen the best response.1i tan is always positive if you take the abs of a and b

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.2Eh? we don't want tan to always be positive... there's no need for that. Keeping the negatives can actually save you some work...
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