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VenomblastBest ResponseYou've already chosen the best response.1
I do not want my answers in degree
 11 months ago

VenomblastBest ResponseYou've already chosen the best response.1
basically what i need help is converting my answer to degree to rad in decimal
 11 months ago

terenzreignzBest ResponseYou've already chosen the best response.1
So you already have your angle in degrees?
 11 months ago

terenzreignzBest ResponseYou've already chosen the best response.1
In that case, if you have it in degrees, to bring it to radians, simply multiply it by the factor \[\huge \frac{\pi}{180^o}\]
 11 months ago

VenomblastBest ResponseYou've already chosen the best response.1
dw:1367393591344:dw
 11 months ago

agent0smithBest ResponseYou've already chosen the best response.2
dw:1367393361730:dw for a number a+bi \[\large r^2 = a^2 + b^2\] tan theta = \[\large \tan \theta = \frac{ b }{a }\] To convert from degrees to radians \[\Large \theta ^{r} = \theta ^{d} \times \frac{ \pi }{180}\] theta d means theta in degrees.
 11 months ago

VenomblastBest ResponseYou've already chosen the best response.1
hey one more question. if 5 was negative would it still be \[\tan \theta b/a\] or will the a be negative?
 11 months ago

agent0smithBest ResponseYou've already chosen the best response.2
Like this? dw:1367393943561:dw \[\tan \theta = \frac{ 12 }{5 }\] which gives theta = 67.4 degrees or 1.18 radians... BUT as you can see, theta is in the third quadrant, so you need to add 180 degrees to 67.4 degrees, or add pi radians to 1.18 radians... giving 247.4 degrees or 4.31 radians. This is why drawing a diagram is helpful.
 11 months ago

VenomblastBest ResponseYou've already chosen the best response.1
no what I am trying to say is, does it matter of a or b is positive or negative or do you just take the absolute value of 12 and 5 when figuring out tan theta
 11 months ago

agent0smithBest ResponseYou've already chosen the best response.2
Oh, no, you use b and a exactly as they are, you can take the abs value, but that just means more work to find the actual angle.
 11 months ago

agent0smithBest ResponseYou've already chosen the best response.2
Because tan is negative in the 2nd and fourth quadrants, so it's helpful to keep the negatives as they are: http://upload.wikimedia.org/wikipedia/commons/thumb/a/a7/All_Students_Take_Calculus.svg/220pxAll_Students_Take_Calculus.svg.png
 11 months ago

VenomblastBest ResponseYou've already chosen the best response.1
i tan is always positive if you take the abs of a and b
 11 months ago

agent0smithBest ResponseYou've already chosen the best response.2
Eh? we don't want tan to always be positive... there's no need for that. Keeping the negatives can actually save you some work...
 11 months ago
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