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DLS
 one year ago
Best ResponseYou've already chosen the best response.0\[\LARGE y=3sinx2cosx\]

DLS
 one year ago
Best ResponseYou've already chosen the best response.0I know \[ \LARGE 1=<sinx+cosx<= \sqrt{2}\]

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1y = 3sinx  2cosx similar with y = 3sinx  2sin(90x) y_minimum when x = 0, it is y = 3(0)  2(1) = 2 y_max when x = 90, it is y = 3(1)  2(0) = 3 so, the range for y is 2 <= y <= 3

DLS
 one year ago
Best ResponseYou've already chosen the best response.0why did you convert cosx to sin(90x) any specific reason?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1that is an identity in trigono :) cos(x) = sin(90x)

DLS
 one year ago
Best ResponseYou've already chosen the best response.0i know that i want to know why did you think of that?

DLS
 one year ago
Best ResponseYou've already chosen the best response.0in this question i mean any specific reason?

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1i trying to make y in sin terms, so that easier to get the output values maybe :)

DLS
 one year ago
Best ResponseYou've already chosen the best response.0does anyone have any other methods ?just curious..thanks @RadEn though!

RadEn
 one year ago
Best ResponseYou've already chosen the best response.1u can make y in cosine terms too y = 3cos(90x)  2cosx you're welcome :)

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1the cosine graph can be though as the sine graph offset by 90 degrees phase. so basically RadEn's method is to simplify the graph. Of course, \(y=3\sin x  2\cos x\) y is maximum when the y=3sin x is max and y=2cos x is min. note that there cannot be negative values. for min y ,it is vice versa. the max value of 3sin x is 3(sinx =1), while the min value of 2 cosx is 0. so that gives 3 the min value 3sin x is 0(sinx =0), while the min value of 2 cosx is 2. so that gives 2 so, 2<=y<=3
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