## ladiesman217 one year ago i give medals and fans

solve $2x ^{2}-8x=-7$

2. .Sam.

add 7 to both sides. $$2x^2 - 8x +7=0$$ then apply the general formula.

$\frac{ -(-8)\sqrt{8x ^{2}-2x*7} }{ 2*2 }$

it's $$x=\frac{-(-8)\pm \sqrt{(-8)^2-4(2)(7)}}{2(2)}$$ though

ok so simplify all that its $\frac{ 8\sqrt{64-14} }{ 4 }$

u forgot to multiply the 14 by 4? the others are right

so $\frac{ 8\sqrt{64-56} }{ 4 }$

yup! you've got it. :)

10. uri

Its soo easy :D

11. .Sam.

loool

so simplify that its $\frac{ 2\sqrt{2} }{ 2 }$

wait. you've missed the plus minus out. $$\frac{8 \pm \sqrt{8}}{4}$$=$$\frac{8 \pm 2\sqrt{2}}{4}=\frac{4 \pm \sqrt{2}}{2}$$

ok thnx