ladiesman217
  • ladiesman217
i give medals and fans
Mathematics
jamiebookeater
  • jamiebookeater
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ladiesman217
  • ladiesman217
solve \[2x ^{2}-8x=-7\]
anonymous
  • anonymous
add 7 to both sides. \(2x^2 - 8x +7=0\) then apply the general formula.

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ladiesman217
  • ladiesman217
\[\frac{ -(-8)\sqrt{8x ^{2}-2x*7} }{ 2*2 }\]
anonymous
  • anonymous
it's \(x=\frac{-(-8)\pm \sqrt{(-8)^2-4(2)(7)}}{2(2)}\) though
ladiesman217
  • ladiesman217
ok so simplify all that its \[\frac{ 8\sqrt{64-14} }{ 4 }\]
anonymous
  • anonymous
u forgot to multiply the 14 by 4? the others are right
ladiesman217
  • ladiesman217
so \[\frac{ 8\sqrt{64-56} }{ 4 }\]
anonymous
  • anonymous
yup! you've got it. :)
uri
  • uri
Its soo easy :D
.Sam.
  • .Sam.
loool
ladiesman217
  • ladiesman217
so simplify that its \[\frac{ 2\sqrt{2} }{ 2 }\]
anonymous
  • anonymous
wait. you've missed the plus minus out. \(\frac{8 \pm \sqrt{8}}{4}\)=\(\frac{8 \pm 2\sqrt{2}}{4}=\frac{4 \pm \sqrt{2}}{2}\)
ladiesman217
  • ladiesman217
ok thnx
anonymous
  • anonymous
you’re welcome :)

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