ladiesman217
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ladiesman217
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solve
\[2x ^{2}8x=7\]


Shadowys
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add 7 to both sides.
\(2x^2  8x +7=0\)
then apply the general formula.

ladiesman217
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\[\frac{ (8)\sqrt{8x ^{2}2x*7} }{ 2*2 }\]

Shadowys
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it's \(x=\frac{(8)\pm \sqrt{(8)^24(2)(7)}}{2(2)}\) though

ladiesman217
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ok so simplify all that its \[\frac{ 8\sqrt{6414} }{ 4 }\]

Shadowys
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u forgot to multiply the 14 by 4? the others are right

ladiesman217
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so \[\frac{ 8\sqrt{6456} }{ 4 }\]

Shadowys
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yup! you've got it. :)

uri
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Its soo easy :D

.Sam.
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loool

ladiesman217
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so simplify that its \[\frac{ 2\sqrt{2} }{ 2 }\]

Shadowys
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wait. you've missed the plus minus out.
\(\frac{8 \pm \sqrt{8}}{4}\)=\(\frac{8 \pm 2\sqrt{2}}{4}=\frac{4 \pm \sqrt{2}}{2}\)

ladiesman217
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ok thnx

Shadowys
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you’re welcome :)