A community for students.
Here's the question you clicked on:
 0 viewing
ladiesman217
 3 years ago
i give medals and fans
ladiesman217
 3 years ago
i give medals and fans

This Question is Closed

ladiesman217
 3 years ago
Best ResponseYou've already chosen the best response.0solve \[2x ^{2}8x=7\]

.Sam.
 3 years ago
Best ResponseYou've already chosen the best response.0Apply http://openstudy.com/users/.sam.#/updates/5181023ce4b0aaab28b79617

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0add 7 to both sides. \(2x^2  8x +7=0\) then apply the general formula.

ladiesman217
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ (8)\sqrt{8x ^{2}2x*7} }{ 2*2 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it's \(x=\frac{(8)\pm \sqrt{(8)^24(2)(7)}}{2(2)}\) though

ladiesman217
 3 years ago
Best ResponseYou've already chosen the best response.0ok so simplify all that its \[\frac{ 8\sqrt{6414} }{ 4 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u forgot to multiply the 14 by 4? the others are right

ladiesman217
 3 years ago
Best ResponseYou've already chosen the best response.0so \[\frac{ 8\sqrt{6456} }{ 4 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup! you've got it. :)

ladiesman217
 3 years ago
Best ResponseYou've already chosen the best response.0so simplify that its \[\frac{ 2\sqrt{2} }{ 2 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait. you've missed the plus minus out. \(\frac{8 \pm \sqrt{8}}{4}\)=\(\frac{8 \pm 2\sqrt{2}}{4}=\frac{4 \pm \sqrt{2}}{2}\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.