Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

A balloonist happens to drop his metal ballpoint pen from his balloon as he is taking notes on his flight. Because his pen has a streamlined shape, air resistance has little effect on its fall. The pen strikes the ground at 22 m/s. How high was the balloon? (Points : 6) 25 m 49 m 850 m 9,500 m

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

u have to find acceleration to find height
the formula that can be used is v^2=u^2+2as
wht is your answer

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\(\vec v_f^2=\vec v_i^2+2\vec a \cdot \vec S\) since \(\vec v_i=0\hat j\),\(\vec v_f=-22\hat j\),\(\vec a=-10\hat j \), plug it in to get, \((-22\hat j)^2=2(-10\hat j) \cdot \vec S\) \(\vec S=-24.2\hat j\) do you need further help?
@Shadowys u could've aloud @megen505 to solve this q' her own and understand. at least a chance

Not the answer you are looking for?

Search for more explanations.

Ask your own question