ladiesman217
  • ladiesman217
i give medals and fans
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ladiesman217
  • ladiesman217
If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it take the baseball to hit the ground? Use the equation \[h=-16t ^{2}+64t+4\]
anonymous
  • anonymous
baseball hits the ground when \(h=0\).
ladiesman217
  • ladiesman217
ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ladiesman217
  • ladiesman217
@Shadowys @UnkleRhaukus @TSwizzle can you help me please
anonymous
  • anonymous
\(h=-16t^2 +64t +4\) when h=0,(the ball hits the ground) \(0=-16t^2 +64t +4\) use the general formula. what did u get?
anonymous
  • anonymous
you need to solve the quadratic equation since h=0 so -16t^+64t+4=0 or 16t^2-64t-4=0 use quadratic formula with a=16 b=-64 c=-4 you will get two roots t=4 sec t=-0.6 but time cannot be negative so neglect the negative value t=4 sec is the required time .
ladiesman217
  • ladiesman217
\[\frac{ -64\sqrt{64^{2}+16*-4} }{ 2*16 }\] \[\frac{ -64\sqrt{64^{2}-64} }{ 32 }\]
anonymous
  • anonymous
it should be +64 outside the root because b=-64 and there is minus in the formula too .
anonymous
  • anonymous
note: it's \(-64 \pm \sqrt{64^2 - (4)(-16)(4)}\) up there.
anonymous
  • anonymous
correct formula is \[\Large =\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
ladiesman217
  • ladiesman217
\[\frac{ 64\sqrt{64^{2}+256} }{32}\]
anonymous
  • anonymous
you miseed plus minus sign :)
anonymous
  • anonymous
yup! simplify and you're done (i guess the editor don't have it. the latex is \pm

Looking for something else?

Not the answer you are looking for? Search for more explanations.