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ladiesman217
 one year ago
Best ResponseYou've already chosen the best response.0If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it take the baseball to hit the ground? Use the equation \[h=16t ^{2}+64t+4\]

mukushla
 one year ago
Best ResponseYou've already chosen the best response.0baseball hits the ground when \(h=0\).

ladiesman217
 one year ago
Best ResponseYou've already chosen the best response.0@Shadowys @UnkleRhaukus @TSwizzle can you help me please

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1\(h=16t^2 +64t +4\) when h=0,(the ball hits the ground) \(0=16t^2 +64t +4\) use the general formula. what did u get?

sami21
 one year ago
Best ResponseYou've already chosen the best response.0you need to solve the quadratic equation since h=0 so 16t^+64t+4=0 or 16t^264t4=0 use quadratic formula with a=16 b=64 c=4 you will get two roots t=4 sec t=0.6 but time cannot be negative so neglect the negative value t=4 sec is the required time .

ladiesman217
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 64\sqrt{64^{2}+16*4} }{ 2*16 }\] \[\frac{ 64\sqrt{64^{2}64} }{ 32 }\]

sami21
 one year ago
Best ResponseYou've already chosen the best response.0it should be +64 outside the root because b=64 and there is minus in the formula too .

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1note: it's \(64 \pm \sqrt{64^2  (4)(16)(4)}\) up there.

sami21
 one year ago
Best ResponseYou've already chosen the best response.0correct formula is \[\Large =\frac{b \pm \sqrt{b^24ac}}{2a}\]

ladiesman217
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 64\sqrt{64^{2}+256} }{32}\]

sami21
 one year ago
Best ResponseYou've already chosen the best response.0you miseed plus minus sign :)

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1yup! simplify and you're done (i guess the editor don't have it. the latex is \pm
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