ohhailayne Group Title 3/m-4+1/3(m-4)=6/m Help! Solving rational expressions one year ago one year ago

1. Linyu Group Title

$\frac{ 3 }{ m }-4+\frac{ 1 }{ 3(m-4) }=\frac{ 6 }{ m }$is it like this?

2. ohhailayne Group Title

yes! @Linyu I just need to know how to do it, my book doesn't give an example for ones like this

3. Linyu Group Title

you need to convert the denominators to the same form$\frac{ a }{ b }+\frac{ c }{ d }=\frac{ ad }{ bd }+\frac{ cb }{ bd }$

4. Linyu Group Title

@ohhailayne are you with me?

5. ohhailayne Group Title

7/m-4? @Linyu

6. Linyu Group Title

hmm... not sure if you catch up. Okay I'll try to solve this one step by step so you could understand

7. ohhailayne Group Title

10/m-4

8. ohhailayne Group Title

I think I've got it? @Linyu

9. Linyu Group Title

$\frac{ 3 }{ m }-\frac{ 4 }{ 1 }+\frac{ 1 }{ 3(m-4) }=\frac{ 6 }{ m }$ convert the denominator into 3m(m-4) we have$\frac{ 3(m-4) }{ 3(m-4) }\times \frac{ 3 }{ m }-\frac{ 3m(m-4) }{ 3m(m-4) }\times \frac{ 4 }{ 1 }+\frac{ m }{ m }\frac{ 1 }{ 3(m-4) }=\frac{ 3(m-4) }{ 3(m-4) }\times \frac{ 6 }{ m }$

10. Linyu Group Title

now all the denominators are the same 3m(m-4) so feel free to cancel them out. And you'll get$3(m-4)\times3-3m(m-4)\times4+m=3(m-4)\times6$

11. ohhailayne Group Title

the problem should be $\frac{ 3 }{ m-4 }+\frac{ 1 }{ 3(m-4) }=\frac{ 6 }{m? }$

12. Linyu Group Title

Oh! that will be better to solve

13. ohhailayne Group Title

yes! so I think the answer is 10/m-4 @Linyu

14. Linyu Group Title

3m(3)+m=3(m-4)(6) 9m+m=18m-72 10m=18m-72 0=8m-72 72=8m m=72/8 m=9

15. Linyu Group Title

the method is the same

16. ohhailayne Group Title

thanks @Linyu

17. Linyu Group Title

I hope you understand. Not only know the answer.