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ohhailayne

  • one year ago

3/m-4+1/3(m-4)=6/m Help! Solving rational expressions

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  1. Linyu
    • one year ago
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    \[\frac{ 3 }{ m }-4+\frac{ 1 }{ 3(m-4) }=\frac{ 6 }{ m }\]is it like this?

  2. ohhailayne
    • one year ago
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    yes! @Linyu I just need to know how to do it, my book doesn't give an example for ones like this

  3. Linyu
    • one year ago
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    you need to convert the denominators to the same form\[\frac{ a }{ b }+\frac{ c }{ d }=\frac{ ad }{ bd }+\frac{ cb }{ bd }\]

  4. Linyu
    • one year ago
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    @ohhailayne are you with me?

  5. ohhailayne
    • one year ago
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    7/m-4? @Linyu

  6. Linyu
    • one year ago
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    hmm... not sure if you catch up. Okay I'll try to solve this one step by step so you could understand

  7. ohhailayne
    • one year ago
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    10/m-4

  8. ohhailayne
    • one year ago
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    I think I've got it? @Linyu

  9. Linyu
    • one year ago
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    \[\frac{ 3 }{ m }-\frac{ 4 }{ 1 }+\frac{ 1 }{ 3(m-4) }=\frac{ 6 }{ m }\] convert the denominator into 3m(m-4) we have\[\frac{ 3(m-4) }{ 3(m-4) }\times \frac{ 3 }{ m }-\frac{ 3m(m-4) }{ 3m(m-4) }\times \frac{ 4 }{ 1 }+\frac{ m }{ m }\frac{ 1 }{ 3(m-4) }=\frac{ 3(m-4) }{ 3(m-4) }\times \frac{ 6 }{ m }\]

  10. Linyu
    • one year ago
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    now all the denominators are the same 3m(m-4) so feel free to cancel them out. And you'll get\[3(m-4)\times3-3m(m-4)\times4+m=3(m-4)\times6\]

  11. ohhailayne
    • one year ago
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    the problem should be \[\frac{ 3 }{ m-4 }+\frac{ 1 }{ 3(m-4) }=\frac{ 6 }{m? }\]

  12. Linyu
    • one year ago
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    Oh! that will be better to solve

  13. ohhailayne
    • one year ago
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    yes! so I think the answer is 10/m-4 @Linyu

  14. Linyu
    • one year ago
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    3m(3)+m=3(m-4)(6) 9m+m=18m-72 10m=18m-72 0=8m-72 72=8m m=72/8 m=9

  15. Linyu
    • one year ago
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    the method is the same

  16. ohhailayne
    • one year ago
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    thanks @Linyu

  17. Linyu
    • one year ago
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    I hope you understand. Not only know the answer.

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