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Tabbiejack

  • one year ago

What is the solution of the system? Use substitution. x = –2y + 10 –6y = 6x – 6 z = –3x + 10y A. x = 9, y = –8, z = 114 B. x = –8, y = 9, z = 114 C. x = –8, y = 114, z = 9 D. x = 114, y = 9, z = –8

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  1. Tabbiejack
    • one year ago
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    @.Sam.

  2. .Sam.
    • one year ago
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    When x = –2y + 10 , From –6y = 6x – 6 –6y = 6( –2y + 10 ) – 6 Solve for y

  3. Tabbiejack
    • one year ago
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    ? I such at this

  4. Tabbiejack
    • one year ago
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    so its C

  5. .Sam.
    • one year ago
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    \[–6y = 6( –2y + 10 ) – 6 \\ \\ -6y=-12y+60-6 \\ \\ 6y=54 \\ \\ y=9\] Get it?

  6. Tabbiejack
    • one year ago
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    no

  7. .Sam.
    • one year ago
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    You distribute 6 into brackets \[–6y = 6( –2y + 10 ) – 6\] \[-6y=-12y+60-6\] Add 12y to both sides, 6y=54 Divide both sides by 6 y=9

  8. Tabbiejack
    • one year ago
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    both sides of what

  9. Tabbiejack
    • one year ago
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    I don't understand this at all and slopes forget it

  10. .Sam.
    • one year ago
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    |dw:1367472748738:dw|

  11. Tabbiejack
    • one year ago
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    ok the answer is A

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