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viniterranovaBest ResponseYou've already chosen the best response.0
this is the answer
 11 months ago

cahitBest ResponseYou've already chosen the best response.0
\[u=(2x^2)\]\[du=2xdx\]\[=x^2x(2x^2)dx\]\[{\int\limits_{}^{}}^{}(2u)u^{12}du\] \[{\int\limits_{}^{}}^{}(u2)u^{12}du\] \[{\int\limits_{}^{}}^{}(u^{13}2u^{12})du\]\[ \frac{ u^{14} }{ 14 } \frac{ u^{15} }{ 15 } \] resubstitute u with 2x^2 and it is the result..
 11 months ago

StaceyBest ResponseYou've already chosen the best response.0
What you wrote is correct except that you did not remove the integral sign after you integrated it.
 11 months ago

viniterranovaBest ResponseYou've already chosen the best response.0
Thanks for the answer.
 10 months ago
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