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viniterranova
 one year ago
Best ResponseYou've already chosen the best response.0this is the answer

cahit
 one year ago
Best ResponseYou've already chosen the best response.0\[u=(2x^2)\]\[du=2xdx\]\[=x^2x(2x^2)dx\]\[{\int\limits_{}^{}}^{}(2u)u^{12}du\] \[{\int\limits_{}^{}}^{}(u2)u^{12}du\] \[{\int\limits_{}^{}}^{}(u^{13}2u^{12})du\]\[ \frac{ u^{14} }{ 14 } \frac{ u^{15} }{ 15 } \] resubstitute u with 2x^2 and it is the result..

Stacey
 one year ago
Best ResponseYou've already chosen the best response.0What you wrote is correct except that you did not remove the integral sign after you integrated it.

viniterranova
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for the answer.
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