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viniterranova

May someone help me with this integral?

  • 11 months ago
  • 11 months ago

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  1. viniterranova
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    • 11 months ago
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    • 11 months ago
  3. viniterranova
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    this is the answer

    • 11 months ago
  4. cahit
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    \[u=(2-x^2)\]\[du=-2xdx\]\[=-x^2x(2-x^2)dx\]\[{-\int\limits_{}^{}}^{}(2-u)u^{12}du\] \[{\int\limits_{}^{}}^{}(u-2)u^{12}du\] \[{\int\limits_{}^{}}^{}(u^{13}-2u^{12})du\]\[ \frac{ u^{14} }{ 14 } -\frac{ u^{15} }{ 15 } \] resubstitute u with 2-x^2 and it is the result..

    • 11 months ago
  5. Stacey
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    |dw:1367804928441:dw|

    • 11 months ago
  6. Stacey
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    What you wrote is correct except that you did not remove the integral sign after you integrated it.

    • 11 months ago
  7. viniterranova
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    Thanks for the answer.

    • 10 months ago
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