## viniterranova Group Title May someone help me with this integral? one year ago one year ago

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1. viniterranova Group Title

2. viniterranova Group Title

3. viniterranova Group Title

4. cahit Group Title

$u=(2-x^2)$$du=-2xdx$$=-x^2x(2-x^2)dx$${-\int\limits_{}^{}}^{}(2-u)u^{12}du$ ${\int\limits_{}^{}}^{}(u-2)u^{12}du$ ${\int\limits_{}^{}}^{}(u^{13}-2u^{12})du$$\frac{ u^{14} }{ 14 } -\frac{ u^{15} }{ 15 }$ resubstitute u with 2-x^2 and it is the result..

5. Stacey Group Title

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6. Stacey Group Title

What you wrote is correct except that you did not remove the integral sign after you integrated it.

7. viniterranova Group Title