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viniterranova

  • 3 years ago

May someone help me with this integral?

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  1. viniterranova
    • 3 years ago
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  2. viniterranova
    • 3 years ago
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  3. viniterranova
    • 3 years ago
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    this is the answer

  4. cahit
    • 3 years ago
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    \[u=(2-x^2)\]\[du=-2xdx\]\[=-x^2x(2-x^2)dx\]\[{-\int\limits_{}^{}}^{}(2-u)u^{12}du\] \[{\int\limits_{}^{}}^{}(u-2)u^{12}du\] \[{\int\limits_{}^{}}^{}(u^{13}-2u^{12})du\]\[ \frac{ u^{14} }{ 14 } -\frac{ u^{15} }{ 15 } \] resubstitute u with 2-x^2 and it is the result..

  5. Stacey
    • 3 years ago
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    |dw:1367804928441:dw|

  6. Stacey
    • 3 years ago
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    What you wrote is correct except that you did not remove the integral sign after you integrated it.

  7. viniterranova
    • 2 years ago
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    Thanks for the answer.

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