anonymous 3 years ago May someone help me with this integral?

1. anonymous

2. anonymous

3. anonymous

this is the answer

4. anonymous

$u=(2-x^2)$$du=-2xdx$$=-x^2x(2-x^2)dx$${-\int\limits_{}^{}}^{}(2-u)u^{12}du$ ${\int\limits_{}^{}}^{}(u-2)u^{12}du$ ${\int\limits_{}^{}}^{}(u^{13}-2u^{12})du$$\frac{ u^{14} }{ 14 } -\frac{ u^{15} }{ 15 }$ resubstitute u with 2-x^2 and it is the result..

5. Stacey

|dw:1367804928441:dw|

6. Stacey

What you wrote is correct except that you did not remove the integral sign after you integrated it.

7. anonymous

Thanks for the answer.