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viniterranova
May someone help me with this integral?
this is the answer
\[u=(2-x^2)\]\[du=-2xdx\]\[=-x^2x(2-x^2)dx\]\[{-\int\limits_{}^{}}^{}(2-u)u^{12}du\] \[{\int\limits_{}^{}}^{}(u-2)u^{12}du\] \[{\int\limits_{}^{}}^{}(u^{13}-2u^{12})du\]\[ \frac{ u^{14} }{ 14 } -\frac{ u^{15} }{ 15 } \] resubstitute u with 2-x^2 and it is the result..
What you wrote is correct except that you did not remove the integral sign after you integrated it.
Thanks for the answer.