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\[x ^{2}-4x=5\]
\(x^2-4x=5\) \(x^2-4x-5=\) use quadratic formula to find x.
Korra stahp. Itachi is at work.

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who is itachi @compassionate?
\[ \begin{array}l\color{red}{\text{D}}\color{orange}{\text{O}}\color{#E6E600}{\text{ }}\color{green}{\text{Y}}\color{blue}{\text{O}}\color{purple}{\text{U}}\color{purple}{\text{ }}\color{red}{\text{E}}\color{orange}{\text{V}}\color{#E6E600}{\text{E}}\color{green}{\text{N}}\color{blue}{\text{ }}\color{purple}{\text{A}}\color{purple}{\text{N}}\color{red}{\text{I}}\color{orange}{\text{M}}\color{#E6E600}{\text{E}}\color{green}{\text{?}}\color{blue}{\text{}}\end{array} \]
\[x=\frac{-b \pm \sqrt{b^2-4 a c}}{2a}\]
the values of a, b nd c can be found by comparing the equation \(x^2-4x-5=0\) with the general equation \(ax^2+bx+c=0\). Does that help? @ladiesman217
ok thnx
so x=-1 & x=5
plz check the signs:)
aren't those the correct signs
nope:(
what are the values of a, b and c?
\[-1^{2}-4*(-1)=5\]
oops reallly soorrry.u r 100% right:)

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