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ladiesman217

  • 3 years ago

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  1. ladiesman217
    • 3 years ago
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    \[x ^{2}-4x=5\]

  2. ajprincess
    • 3 years ago
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    \(x^2-4x=5\) \(x^2-4x-5=\) use quadratic formula to find x.

  3. Compassionate
    • 3 years ago
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    Korra stahp. Itachi is at work.

  4. ajprincess
    • 3 years ago
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    who is itachi @compassionate?

  5. Compassionate
    • 3 years ago
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    \[ \begin{array}l\color{red}{\text{D}}\color{orange}{\text{O}}\color{#E6E600}{\text{ }}\color{green}{\text{Y}}\color{blue}{\text{O}}\color{purple}{\text{U}}\color{purple}{\text{ }}\color{red}{\text{E}}\color{orange}{\text{V}}\color{#E6E600}{\text{E}}\color{green}{\text{N}}\color{blue}{\text{ }}\color{purple}{\text{A}}\color{purple}{\text{N}}\color{red}{\text{I}}\color{orange}{\text{M}}\color{#E6E600}{\text{E}}\color{green}{\text{?}}\color{blue}{\text{}}\end{array} \]

  6. austinL
    • 3 years ago
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    \[x=\frac{-b \pm \sqrt{b^2-4 a c}}{2a}\]

  7. ajprincess
    • 3 years ago
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    the values of a, b nd c can be found by comparing the equation \(x^2-4x-5=0\) with the general equation \(ax^2+bx+c=0\). Does that help? @ladiesman217

  8. ladiesman217
    • 3 years ago
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    ok thnx

  9. ladiesman217
    • 3 years ago
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    so x=-1 & x=5

  10. ajprincess
    • 3 years ago
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    plz check the signs:)

  11. ladiesman217
    • 3 years ago
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    aren't those the correct signs

  12. ajprincess
    • 3 years ago
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    nope:(

  13. ajprincess
    • 3 years ago
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    what are the values of a, b and c?

  14. ladiesman217
    • 3 years ago
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    \[-1^{2}-4*(-1)=5\]

  15. ajprincess
    • 3 years ago
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    oops reallly soorrry.u r 100% right:)

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