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bfinn4

  • 3 years ago

could anyone help me with the half angle formulas for tan. i have tan(5pi)/4 i can get everything plugged into the formula but i am having trouble simplify @precal

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  1. ajprincess
    • 3 years ago
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    Do u want to find the value of tan(5pi)/4?

  2. ajprincess
    • 3 years ago
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    @bfinn4

  3. bfinn4
    • 3 years ago
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    yes the exact value

  4. bfinn4
    • 3 years ago
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    i am having trouble simplify all the radical stuff..and i dont have a way to type a radical into this web site so i dont know how to show you my work?

  5. bfinn4
    • 3 years ago
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    oops i typed that woring i want the value of tan(5pi)/8

  6. bfinn4
    • 3 years ago
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    or tan [((5pi)/4)/2]

  7. ajprincess
    • 3 years ago
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    `\(sqrt{}\)` u can use this to type radicals.

  8. ajprincess
    • 3 years ago
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    \[\tan\theta=\frac{2tan(\frac{\theta}{2})}{1-tan^2(\frac{\theta}{2})}\]

  9. ajprincess
    • 2 years ago
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    \[\frac{\theta}{2}=\frac{5\pi}{8}\] \[\theta=\frac{5\pi}{4}\] plugging this in the formula gives u \[\tan\frac{5\pi}{4}=\frac{2tan\frac{5\pi}{8}}{1-tan^2\frac{5\pi}{8}}\] \[\pi=180\] so \[\frac{5\pi}{4}=225\] do u knw the value of tan225?

  10. bfinn4
    • 2 years ago
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    1

  11. ajprincess
    • 2 years ago
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    yup good:)

  12. ajprincess
    • 2 years ago
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    so \[\tan\frac{5\pi}{4}=1\]. \[1=\frac{2tan\frac{5\pi}{8}}{1-tan^2\frac{5\pi}{8}}\] Let us assume \[x=\tan\frac{5\pi}{8}\] \[1=\frac{2x}{1-x^2}\] \[1-x^2=2x\] \[x^2+2x-1=0\] Can u find x?

  13. ajprincess
    • 2 years ago
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    @bfinn4

  14. bfinn4
    • 2 years ago
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    i have to go to class but yes i can find x ...i will do it right after geology.

  15. ajprincess
    • 2 years ago
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    k 5n:)

  16. precal
    • 2 years ago
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    @ajprincess she did a great job helping you

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