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could anyone help me with the half angle formulas for tan. i have tan(5pi)/4 i can get everything plugged into the formula but i am having trouble simplify @precal

Mathematics
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Do u want to find the value of tan(5pi)/4?
yes the exact value

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i am having trouble simplify all the radical stuff..and i dont have a way to type a radical into this web site so i dont know how to show you my work?
oops i typed that woring i want the value of tan(5pi)/8
or tan [((5pi)/4)/2]
`\(sqrt{}\)` u can use this to type radicals.
\[\tan\theta=\frac{2tan(\frac{\theta}{2})}{1-tan^2(\frac{\theta}{2})}\]
\[\frac{\theta}{2}=\frac{5\pi}{8}\] \[\theta=\frac{5\pi}{4}\] plugging this in the formula gives u \[\tan\frac{5\pi}{4}=\frac{2tan\frac{5\pi}{8}}{1-tan^2\frac{5\pi}{8}}\] \[\pi=180\] so \[\frac{5\pi}{4}=225\] do u knw the value of tan225?
1
yup good:)
so \[\tan\frac{5\pi}{4}=1\]. \[1=\frac{2tan\frac{5\pi}{8}}{1-tan^2\frac{5\pi}{8}}\] Let us assume \[x=\tan\frac{5\pi}{8}\] \[1=\frac{2x}{1-x^2}\] \[1-x^2=2x\] \[x^2+2x-1=0\] Can u find x?
i have to go to class but yes i can find x ...i will do it right after geology.
k 5n:)
@ajprincess she did a great job helping you

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