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Christos
Group Title
Help me solve lim(x>2) x(x1)(x+1) I merely wish to understand the logic behind it
 one year ago
 one year ago
Christos Group Title
Help me solve lim(x>2) x(x1)(x+1) I merely wish to understand the logic behind it
 one year ago
 one year ago

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@ajprincess
 one year ago

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@LoveYou*69
 one year ago

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@ganeshie8
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
first plug in the value given as the value that x tends to in place of x in given limit. in this case it is given that x>2. so plug in 2 in x(x1)(x+1) and find the value. in some cases when u plug in the values that x tends to, u get zero. in that cases u try to simplify as much as possible and then plug in the value and simplify. Let me give u an example for such cases. lim x^29/x3 x>3 when u plug in x=3 u get (3)^29/33=99/0=0/0indeterminate. x^29/x3=(x3)(x+3)/(x3)=x+3 nw plug in 3 , u get 3+3=6. so that is the answer for question lim x^29/x3 x>3. Does that help? @christos
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
Sorry if I have confused u
 one year ago

BrLima Group TitleBest ResponseYou've already chosen the best response.1
Yes, the answers is 6. The way to find it was described by @ajprincess. When the function is continuous you just have to plug in the value. However, if the function isn't continous on the specific point you'll try to simplify the function. After the simplification you'll have a new function that is continuous, so you can just plug in the value to find the limit.
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
6 or lim6 ?
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
dw:1367516895165:dw
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
welcome:) do u get it?
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
How do I solve lim(x>1) (x^41)/(x1) it gives me 0
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
nw try to simplify it as possible.
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
Please give me steps, just on this one, then I will get it
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\(x^41=(x^2)^2(1^2)^2=(x^21^2)(x^2+1^2)=(x1)(x+1)(x^2+1)\) \[\frac{x^41}{x1}=\frac{(x1)(x+1)(x^2+1)}{x1}\] \[=?\]
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\[\frac{(x1)(x+1)(x^2+1)}{x1}=\frac{\cancel{(x1)}(x+1)(x^2+1)}{\cancel{x1}}\] \[=(x+1)(x^2+1)\] nw plug in 1 in place of x nd find the value
 one year ago

Christos Group TitleBest ResponseYou've already chosen the best response.0
How did you get from here (x2−12)(x2+12) to here (x−1)(x+1)(x2+1)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\((x^21^2)=(x1)(x+1)\) difference of squares. so \((x^21^2)(x^2+1)=(x1)(x+1)(x^2+1)\)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\((x+1)(x^2+1)\) when x=1 \((1+1)(1+1)\) \(=2*2\)
 one year ago
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