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Christos
 3 years ago
Help me solve lim(x>2) x(x1)(x+1) I merely wish to understand the logic behind it
Christos
 3 years ago
Help me solve lim(x>2) x(x1)(x+1) I merely wish to understand the logic behind it

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ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.2first plug in the value given as the value that x tends to in place of x in given limit. in this case it is given that x>2. so plug in 2 in x(x1)(x+1) and find the value. in some cases when u plug in the values that x tends to, u get zero. in that cases u try to simplify as much as possible and then plug in the value and simplify. Let me give u an example for such cases. lim x^29/x3 x>3 when u plug in x=3 u get (3)^29/33=99/0=0/0indeterminate. x^29/x3=(x3)(x+3)/(x3)=x+3 nw plug in 3 , u get 3+3=6. so that is the answer for question lim x^29/x3 x>3. Does that help? @christos

ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.2Sorry if I have confused u

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, the answers is 6. The way to find it was described by @ajprincess. When the function is continuous you just have to plug in the value. However, if the function isn't continous on the specific point you'll try to simplify the function. After the simplification you'll have a new function that is continuous, so you can just plug in the value to find the limit.

ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1367516895165:dw

ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.2welcome:) do u get it?

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0How do I solve lim(x>1) (x^41)/(x1) it gives me 0

ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.2nw try to simplify it as possible.

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0Please give me steps, just on this one, then I will get it

ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.2\(x^41=(x^2)^2(1^2)^2=(x^21^2)(x^2+1^2)=(x1)(x+1)(x^2+1)\) \[\frac{x^41}{x1}=\frac{(x1)(x+1)(x^2+1)}{x1}\] \[=?\]

ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{(x1)(x+1)(x^2+1)}{x1}=\frac{\cancel{(x1)}(x+1)(x^2+1)}{\cancel{x1}}\] \[=(x+1)(x^2+1)\] nw plug in 1 in place of x nd find the value

Christos
 3 years ago
Best ResponseYou've already chosen the best response.0How did you get from here (x2−12)(x2+12) to here (x−1)(x+1)(x2+1)

ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.2\((x^21^2)=(x1)(x+1)\) difference of squares. so \((x^21^2)(x^2+1)=(x1)(x+1)(x^2+1)\)

ajprincess
 3 years ago
Best ResponseYou've already chosen the best response.2\((x+1)(x^2+1)\) when x=1 \((1+1)(1+1)\) \(=2*2\)
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