## Christos Group Title Help me solve lim(x-->2) x(x-1)(x+1) I merely wish to understand the logic behind it one year ago one year ago

1. Christos Group Title

what...?

2. Christos Group Title

@ajprincess

3. Christos Group Title

@LoveYou*69

4. Christos Group Title

@ganeshie8

5. ajprincess Group Title

first plug in the value given as the value that x tends to in place of x in given limit. in this case it is given that x->2. so plug in 2 in x(x-1)(x+1) and find the value. in some cases when u plug in the values that x tends to, u get zero. in that cases u try to simplify as much as possible and then plug in the value and simplify. Let me give u an example for such cases. lim x^2-9/x-3 x->3 when u plug in x=3 u get (3)^2-9/3-3=9-9/0=0/0-indeterminate. x^2-9/x-3=(x-3)(x+3)/(x-3)=x+3 nw plug in 3 , u get 3+3=6. so that is the answer for question lim x^2-9/x-3 x->3. Does that help? @christos

6. ajprincess Group Title

Sorry if I have confused u

7. BrLima Group Title

Yes, the answers is 6. The way to find it was described by @ajprincess. When the function is continuous you just have to plug in the value. However, if the function isn't continous on the specific point you'll try to simplify the function. After the simplification you'll have a new function that is continuous, so you can just plug in the value to find the limit.

8. Christos Group Title

6 or lim6 ?

9. ajprincess Group Title

jst 6.

10. ajprincess Group Title

|dw:1367516895165:dw|

11. Christos Group Title

thx man

12. ajprincess Group Title

welcome:) do u get it?

13. Christos Group Title

How do I solve lim(x--->1) (x^4-1)/(x-1) it gives me 0

14. ajprincess Group Title

nw try to simplify it as possible.

15. Christos Group Title

Please give me steps, just on this one, then I will get it

16. ajprincess Group Title

$$x^4-1=(x^2)^2-(1^2)^2=(x^2-1^2)(x^2+1^2)=(x-1)(x+1)(x^2+1)$$ $\frac{x^4-1}{x-1}=\frac{(x-1)(x+1)(x^2+1)}{x-1}$ $=?$

17. Christos Group Title

1

18. ajprincess Group Title

$\frac{(x-1)(x+1)(x^2+1)}{x-1}=\frac{\cancel{(x-1)}(x+1)(x^2+1)}{\cancel{x-1}}$ $=(x+1)(x^2+1)$ nw plug in 1 in place of x nd find the value

19. Christos Group Title

How did you get from here (x2−12)(x2+12) to here (x−1)(x+1)(x2+1)

20. ajprincess Group Title

$$(x^2-1^2)=(x-1)(x+1)$$ difference of squares. so $$(x^2-1^2)(x^2+1)=(x-1)(x+1)(x^2+1)$$

21. Christos Group Title

its 3??

22. ajprincess Group Title

$$(x+1)(x^2+1)$$ when x=1 $$(1+1)(1+1)$$ $$=2*2$$

23. Christos Group Title

I see!