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cantverify1

  • 3 years ago

Please Help, or Teach me. i miss this lesson today and this was the given assignment. 1.) 2a+b a+4b a-7b ___________ - ____________ - ____________ a^2-3ab+2b^2 a^2-4ab+3b^2 a^2-5ab+6a^2 2.) 6m 2n ____________ - ___________ m^2+5m+6 m^2+6m+9 3.) m+2 m _____ - _____ 3m+15 5m+25 Thanks in Advance

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  1. ajprincess
    • 3 years ago
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    r u familiar with factorising?

  2. cantverify1
    • 3 years ago
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    yes i am

  3. ajprincess
    • 3 years ago
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    good:) can u factorise a^2-3ab+2b^2?

  4. cantverify1
    • 3 years ago
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    is it 2ab^2?

  5. ajprincess
    • 3 years ago
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    Nope:( Can u tell me two factors of 2 such that their sum is -3?

  6. cantverify1
    • 3 years ago
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    (x-2)(x-1)?

  7. ajprincess
    • 3 years ago
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    a^2-3ab+2b^2 the factors of 2 whose sum is -3 are -1 nd -2. split the middle term -3ab using this. then u will get a^2-2ab-ab+2b^2 =a(a-2b)-b(a-2b) =(a-2b)(a-b) Is it clear?

  8. cantverify1
    • 3 years ago
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    so the factor of the a^2-4ab+3b^2 is -3 -1 also a^2-3ab-ab+3b^2 =a(a-3b)-b(a-3b) =(a-3b)(a-b)?

  9. cantverify1
    • 3 years ago
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    a^2-5ab+6a^2 = (a-2)(a-3) i dont know next

  10. cantverify1
    • 3 years ago
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    can u help me with any number there, so that i can answer the others by myself.

  11. ajprincess
    • 3 years ago
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    good:) so a^2-3ab+2b^2=(a-2b)(a-b) a^2-4ab+3b^2=(a-3b)(a-b) a^2-5ab+6a^2 = (a-2)(a-3)

  12. ajprincess
    • 3 years ago
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    can u find thw l.c.m of (a-2b)(a-b), (a-3b)(a-b) and (a-2)(a-3)?

  13. cantverify1
    • 3 years ago
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    i dont know how.

  14. cantverify1
    • 3 years ago
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    may i ask if this is correct a^2-5ab+6a^2 = (a-2)(a-3) because i didnt split it yet

  15. ajprincess
    • 3 years ago
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    nope:( sorry i didnt notice it. if it is a^2-5ab+6b^2, then a^2-5ab+6b^2= (a-2b)(a-3b)

  16. cantverify1
    • 3 years ago
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    so is it all right if a^2-3ab+2b^2=(a-1b)(a-2b) a^2-4ab+3b^2=(a-1b)(a-3b) ?

  17. ajprincess
    • 3 years ago
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    yup:)

  18. cantverify1
    • 3 years ago
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    ajprincess, can you solve any number there then ill do the rest so that i can follow. because its 2am here and i need to sleep thanks for your help btw

  19. ajprincess
    • 3 years ago
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    is it a^2-5ab+6a^2? or a^2-5ab+6b^2?

  20. cantverify1
    • 3 years ago
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    its written a^2-5ab+6a^2? but i think it b

  21. ajprincess
    • 3 years ago
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    |dw:1367518581180:dw||dw:1367518676999:dw||dw:1367518812028:dw|

  22. cantverify1
    • 3 years ago
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    Thank you very much ajprincess

  23. cantverify1
    • 3 years ago
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    aj princess may i ask last one question? where did you start cancelling?

  24. ajprincess
    • 3 years ago
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    cancel what?

  25. cantverify1
    • 3 years ago
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    so you didnt cancel anything?

  26. ajprincess
    • 3 years ago
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    First I factorised the denominators. then i found lcm.

  27. ajprincess
    • 3 years ago
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    after finding the lcm i multiplied each fraction both up and down to make them have the common denominator. the common denominator is (m+3)^2(m+2) but the denominator of the first fraction is (m+3)(m+2). To make it (m+3)^2(m+2) i multiplied by (m+3). if i multiplied the denominator then i should multiply the numerator by the same in order to keep the fraction the same. getiing it?

  28. ajprincess
    • 3 years ago
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    Really sorry. have to leave nw.:(

  29. cantverify1
    • 3 years ago
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    yes, i reviewed again the answer you've given and it canceling anything isnt neccessary

  30. cantverify1
    • 3 years ago
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    Thank you very much again ajprincess.

  31. ajprincess
    • 3 years ago
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    Welcome:)

  32. cantverify1
    • 3 years ago
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    ok then next time you'll find me in a different name because i cant verify any account. i dont know why :)

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