anonymous
  • anonymous
Please Help, or Teach me. i miss this lesson today and this was the given assignment. 1.) 2a+b a+4b a-7b ___________ - ____________ - ____________ a^2-3ab+2b^2 a^2-4ab+3b^2 a^2-5ab+6a^2 2.) 6m 2n ____________ - ___________ m^2+5m+6 m^2+6m+9 3.) m+2 m _____ - _____ 3m+15 5m+25 Thanks in Advance
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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ajprincess
  • ajprincess
r u familiar with factorising?
anonymous
  • anonymous
yes i am
ajprincess
  • ajprincess
good:) can u factorise a^2-3ab+2b^2?

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anonymous
  • anonymous
is it 2ab^2?
ajprincess
  • ajprincess
Nope:( Can u tell me two factors of 2 such that their sum is -3?
anonymous
  • anonymous
(x-2)(x-1)?
ajprincess
  • ajprincess
a^2-3ab+2b^2 the factors of 2 whose sum is -3 are -1 nd -2. split the middle term -3ab using this. then u will get a^2-2ab-ab+2b^2 =a(a-2b)-b(a-2b) =(a-2b)(a-b) Is it clear?
anonymous
  • anonymous
so the factor of the a^2-4ab+3b^2 is -3 -1 also a^2-3ab-ab+3b^2 =a(a-3b)-b(a-3b) =(a-3b)(a-b)?
anonymous
  • anonymous
a^2-5ab+6a^2 = (a-2)(a-3) i dont know next
anonymous
  • anonymous
can u help me with any number there, so that i can answer the others by myself.
ajprincess
  • ajprincess
good:) so a^2-3ab+2b^2=(a-2b)(a-b) a^2-4ab+3b^2=(a-3b)(a-b) a^2-5ab+6a^2 = (a-2)(a-3)
ajprincess
  • ajprincess
can u find thw l.c.m of (a-2b)(a-b), (a-3b)(a-b) and (a-2)(a-3)?
anonymous
  • anonymous
i dont know how.
anonymous
  • anonymous
may i ask if this is correct a^2-5ab+6a^2 = (a-2)(a-3) because i didnt split it yet
ajprincess
  • ajprincess
nope:( sorry i didnt notice it. if it is a^2-5ab+6b^2, then a^2-5ab+6b^2= (a-2b)(a-3b)
anonymous
  • anonymous
so is it all right if a^2-3ab+2b^2=(a-1b)(a-2b) a^2-4ab+3b^2=(a-1b)(a-3b) ?
ajprincess
  • ajprincess
yup:)
anonymous
  • anonymous
ajprincess, can you solve any number there then ill do the rest so that i can follow. because its 2am here and i need to sleep thanks for your help btw
ajprincess
  • ajprincess
is it a^2-5ab+6a^2? or a^2-5ab+6b^2?
anonymous
  • anonymous
its written a^2-5ab+6a^2? but i think it b
ajprincess
  • ajprincess
|dw:1367518581180:dw||dw:1367518676999:dw||dw:1367518812028:dw|
anonymous
  • anonymous
Thank you very much ajprincess
anonymous
  • anonymous
aj princess may i ask last one question? where did you start cancelling?
ajprincess
  • ajprincess
cancel what?
anonymous
  • anonymous
so you didnt cancel anything?
ajprincess
  • ajprincess
First I factorised the denominators. then i found lcm.
ajprincess
  • ajprincess
after finding the lcm i multiplied each fraction both up and down to make them have the common denominator. the common denominator is (m+3)^2(m+2) but the denominator of the first fraction is (m+3)(m+2). To make it (m+3)^2(m+2) i multiplied by (m+3). if i multiplied the denominator then i should multiply the numerator by the same in order to keep the fraction the same. getiing it?
ajprincess
  • ajprincess
Really sorry. have to leave nw.:(
anonymous
  • anonymous
yes, i reviewed again the answer you've given and it canceling anything isnt neccessary
anonymous
  • anonymous
Thank you very much again ajprincess.
ajprincess
  • ajprincess
Welcome:)
anonymous
  • anonymous
ok then next time you'll find me in a different name because i cant verify any account. i dont know why :)

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