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r u familiar with factorising?

yes i am

good:)
can u factorise a^2-3ab+2b^2?

is it 2ab^2?

Nope:(
Can u tell me two factors of 2 such that their sum is -3?

(x-2)(x-1)?

so the factor of the a^2-4ab+3b^2 is -3 -1 also
a^2-3ab-ab+3b^2
=a(a-3b)-b(a-3b)
=(a-3b)(a-b)?

a^2-5ab+6a^2 = (a-2)(a-3)
i dont know next

can u help me with any number there, so that i can answer the others by myself.

good:)
so
a^2-3ab+2b^2=(a-2b)(a-b)
a^2-4ab+3b^2=(a-3b)(a-b)
a^2-5ab+6a^2 = (a-2)(a-3)

can u find thw l.c.m of (a-2b)(a-b), (a-3b)(a-b) and (a-2)(a-3)?

i dont know how.

may i ask if this is correct a^2-5ab+6a^2 = (a-2)(a-3) because i didnt split it yet

nope:( sorry i didnt notice it.
if it is a^2-5ab+6b^2, then
a^2-5ab+6b^2= (a-2b)(a-3b)

so is it all right if a^2-3ab+2b^2=(a-1b)(a-2b)
a^2-4ab+3b^2=(a-1b)(a-3b) ?

yup:)

is it a^2-5ab+6a^2? or a^2-5ab+6b^2?

its written a^2-5ab+6a^2? but i think it b

|dw:1367518581180:dw||dw:1367518676999:dw||dw:1367518812028:dw|

Thank you very much ajprincess

aj princess may i ask last one question? where did you start cancelling?

cancel what?

so you didnt cancel anything?

First I factorised the denominators.
then i found lcm.

Really sorry. have to leave nw.:(

yes, i reviewed again the answer you've given and it canceling anything isnt neccessary

Thank you very much again ajprincess.

Welcome:)