anonymous
  • anonymous
2c/c-4-2=4/c+5 help please! extremely behind, and need to get caught up
Mathematics
schrodinger
  • schrodinger
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AravindG
  • AravindG
first cancel off 2 on both sides
anonymous
  • anonymous
okk then what
anonymous
  • anonymous

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AravindG
  • AravindG
then cross multiply
anonymous
  • anonymous
so what would that leavee me with? i dont understand
AravindG
  • AravindG
|dw:1367519309439:dw|
AravindG
  • AravindG
use that ^
anonymous
  • anonymous
would it be c(c+5)/4(c-4) @AravindG

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