anonymous
  • anonymous
calculus help...last two questions...
Differential Equations
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
http://assets.openstudy.com/updates/attachments/517d65e4e4b0be6b54ab31bc-best_mathematician-1367172592503-3.png
anonymous
  • anonymous
@electrokid can u help me with last two
anonymous
  • anonymous
how were you able to solve the first ones? You have to picture it and draw it first. Just a little bit of imagination gives the answer right away.

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FibonacciChick666
  • FibonacciChick666
so you got the first three right? now you want a function that shows \[2[ \mathsf { {r}}(t)]\] So what was our original r(t)
FibonacciChick666
  • FibonacciChick666
btw this isn't dif eq
anonymous
  • anonymous
r(t) = (t-sint)i + (1-cost)j so if it is 2[r(t)] = (2t-2sint)i + (2-2cost)j is it correct?
anonymous
  • anonymous
i am not smart
anonymous
  • anonymous
@electrokid is this what you talking about? |dw:1367589459350:dw| i got this part but what abt rest part @FibonacciChick666 r(t) = (t-sint)i + (1-cost)j so if it is 2[r(t)] = (2t-2sint)i + (2-2cost)j is it correct?
anonymous
  • anonymous
|dw:1367594323679:dw| this is the diagram I was talking about
anonymous
  • anonymous
how does this diagram relates with vectors
anonymous
  • anonymous
|dw:1367594594073:dw| r(t) is the position vector of that small balck strip
anonymous
  • anonymous
oh gotcha...so circumference is the vector function that models the behavior
anonymous
  • anonymous
r(t) is the vector function linear distance travelled is easier to analyse by considering curcumference distances
anonymous
  • anonymous
r(t) is the position of that small strip on the bigger loop with radius R "r" = radius of smaller loop (confusing symbol, so use another one maybe "a" find a relation between R and "a"
anonymous
  • anonymous
R = 2r....?
anonymous
  • anonymous
then what is the relation between "r(t)" and R?
anonymous
  • anonymous
r(t) = 4piR...?
anonymous
  • anonymous
wait r(t) = 2R...correct?
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
wow...how did u do that
anonymous
  • anonymous
never mind how. but do you see how the question works?
anonymous
  • anonymous
I'll let @FibonacciChick666 continue from here
anonymous
  • anonymous
ya circumference is equal to 2pi. It takes 6seconds approx for that circle to complete one revolution

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