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calculus help...last two questions...

Differential Equations
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@electrokid can u help me with last two
how were you able to solve the first ones? You have to picture it and draw it first. Just a little bit of imagination gives the answer right away.

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Other answers:

so you got the first three right? now you want a function that shows \[2[ \mathsf { {r}}(t)]\] So what was our original r(t)
btw this isn't dif eq
r(t) = (t-sint)i + (1-cost)j so if it is 2[r(t)] = (2t-2sint)i + (2-2cost)j is it correct?
i am not smart
@electrokid is this what you talking about? |dw:1367589459350:dw| i got this part but what abt rest part @FibonacciChick666 r(t) = (t-sint)i + (1-cost)j so if it is 2[r(t)] = (2t-2sint)i + (2-2cost)j is it correct?
|dw:1367594323679:dw| this is the diagram I was talking about
how does this diagram relates with vectors
|dw:1367594594073:dw| r(t) is the position vector of that small balck strip
oh gotcha...so circumference is the vector function that models the behavior
r(t) is the vector function linear distance travelled is easier to analyse by considering curcumference distances
r(t) is the position of that small strip on the bigger loop with radius R "r" = radius of smaller loop (confusing symbol, so use another one maybe "a" find a relation between R and "a"
R = 2r....?
then what is the relation between "r(t)" and R?
r(t) = 4piR...?
wait r(t) = 2R...correct?
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wow...how did u do that
never mind how. but do you see how the question works?
I'll let @FibonacciChick666 continue from here
ya circumference is equal to 2pi. It takes 6seconds approx for that circle to complete one revolution

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