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 one year ago
What is the average kinetic energy of 1 mole of a gas at 125 Kelvin? (R = 8.314 J/Kmol)
A. 1.04 x 10^3 J
B. 3.12 x 10^3 J
C. 1.56 x 10^3 J
D. 1.77 x 10^3 J
 one year ago
What is the average kinetic energy of 1 mole of a gas at 125 Kelvin? (R = 8.314 J/Kmol) A. 1.04 x 10^3 J B. 3.12 x 10^3 J C. 1.56 x 10^3 J D. 1.77 x 10^3 J

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chmvijay
 one year ago
Best ResponseYou've already chosen the best response.0do you know equation for average kinetic energy

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.1From kinetic theory, \[E_K=\frac{1}{2}m<c^2>=\frac{3}{2}k_BT\]  We can say that \[E_K=\frac{3}{2}k_BT\] \(k_B=Boltzmann~Constant=1.38 \times 10^{23}m^2kgs^{2}K^{1}\) Substitute in \[E_K=\frac{3}{2}(1.38 \times 10^{23})(125)=?\] Multiply that by avogadro number \(N_A\) gives average kinetic energy

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.1@chmvijay do you have a different approach? I can't think of one relating R

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.1yeah but the problem is the question includes (R = 8.314 J/Kmol)

Pumpkin890
 one year ago
Best ResponseYou've already chosen the best response.0Did anyone ever figure out how to do this?
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