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anonymous
 3 years ago
What is the average kinetic energy of 1 mole of a gas at 125 Kelvin? (R = 8.314 J/Kmol)
A. 1.04 x 10^3 J
B. 3.12 x 10^3 J
C. 1.56 x 10^3 J
D. 1.77 x 10^3 J
anonymous
 3 years ago
What is the average kinetic energy of 1 mole of a gas at 125 Kelvin? (R = 8.314 J/Kmol) A. 1.04 x 10^3 J B. 3.12 x 10^3 J C. 1.56 x 10^3 J D. 1.77 x 10^3 J

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chmvijay
 3 years ago
Best ResponseYou've already chosen the best response.0do you know equation for average kinetic energy

.Sam.
 3 years ago
Best ResponseYou've already chosen the best response.1From kinetic theory, \[E_K=\frac{1}{2}m<c^2>=\frac{3}{2}k_BT\]  We can say that \[E_K=\frac{3}{2}k_BT\] \(k_B=Boltzmann~Constant=1.38 \times 10^{23}m^2kgs^{2}K^{1}\) Substitute in \[E_K=\frac{3}{2}(1.38 \times 10^{23})(125)=?\] Multiply that by avogadro number \(N_A\) gives average kinetic energy

.Sam.
 3 years ago
Best ResponseYou've already chosen the best response.1@chmvijay do you have a different approach? I can't think of one relating R

.Sam.
 3 years ago
Best ResponseYou've already chosen the best response.1yeah but the problem is the question includes (R = 8.314 J/Kmol)

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Did anyone ever figure out how to do this?
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