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Doggiebounce
Group Title
What is the average kinetic energy of 1 mole of a gas at 125 Kelvin? (R = 8.314 J/Kmol)
A. 1.04 x 10^3 J
B. 3.12 x 10^3 J
C. 1.56 x 10^3 J
D. 1.77 x 10^3 J
 one year ago
 one year ago
Doggiebounce Group Title
What is the average kinetic energy of 1 mole of a gas at 125 Kelvin? (R = 8.314 J/Kmol) A. 1.04 x 10^3 J B. 3.12 x 10^3 J C. 1.56 x 10^3 J D. 1.77 x 10^3 J
 one year ago
 one year ago

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chmvijay Group TitleBest ResponseYou've already chosen the best response.0
do you know equation for average kinetic energy
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.1
From kinetic theory, \[E_K=\frac{1}{2}m<c^2>=\frac{3}{2}k_BT\]  We can say that \[E_K=\frac{3}{2}k_BT\] \(k_B=Boltzmann~Constant=1.38 \times 10^{23}m^2kgs^{2}K^{1}\) Substitute in \[E_K=\frac{3}{2}(1.38 \times 10^{23})(125)=?\] Multiply that by avogadro number \(N_A\) gives average kinetic energy
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.1
@chmvijay do you have a different approach? I can't think of one relating R
 one year ago

chmvijay Group TitleBest ResponseYou've already chosen the best response.0
ur right i is 3KT/2
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.1
yeah but the problem is the question includes (R = 8.314 J/Kmol)
 one year ago

Pumpkin890 Group TitleBest ResponseYou've already chosen the best response.0
Did anyone ever figure out how to do this?
 one year ago
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