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msingh

  • 3 years ago

plse solve this

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  1. ajprincess
    • 3 years ago
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    \[\theta=\cos^{-1}\frac{-\sqrt3}{2}\] \[\cos\theta=\frac{-\sqrt3}{2}\] So vat is the value of \(\theta\)? @msingh

  2. ajprincess
    • 3 years ago
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    cos60=1/2

  3. ajprincess
    • 3 years ago
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    well ya. but there is another value.

  4. msingh
    • 3 years ago
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    -cos30

  5. apple_pi
    • 3 years ago
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    why do you need to find theta? It's just cos(A+B)

  6. ajprincess
    • 3 years ago
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    hw abt 5pi/6?

  7. ajprincess
    • 3 years ago
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    i mean cos(5pi/6)

  8. msingh
    • 3 years ago
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    okay

  9. ajprincess
    • 3 years ago
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    \[\cos(\frac{5\pi}{6}+\frac{\pi}{4})=?\]

  10. ajprincess
    • 3 years ago
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    nw as @apple_pi mentioned u can use \(\cos(A+B)=\cos A\cos B-\sin A\sin B\).

  11. apple_pi
    • 3 years ago
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    @ajprincess why did you find theta? You could just leave it as acos(...), then cos(acos(...)) would cancel and then use pythagorus to find sin(acos(...))

  12. ajprincess
    • 3 years ago
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    well i found it easy to find theta first nd then do..:)

  13. apple_pi
    • 3 years ago
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    ok whatever suits you :p

  14. msingh
    • 3 years ago
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    @ajprincess can u plse tell me exact answer

  15. ajprincess
    • 3 years ago
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    Well i am really sorry. I am nt supposed to give direct answers. pls check the code of conduct

  16. ajprincess
    • 3 years ago
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    |dw:1367584877456:dw|

  17. ajprincess
    • 3 years ago
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    plug in the values nd simplify

  18. msingh
    • 3 years ago
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    yes, after this, i m getting cos(5pi/6)-sin(5pi/6)

  19. ajprincess
    • 3 years ago
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    what is cos(pi/4)?

  20. msingh
    • 3 years ago
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    oh again i did wroong i place 1 as it is 1/ root2

  21. ajprincess
    • 3 years ago
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    what are cos(5pi/6),sin(pi/4) and sin(5pi/6)?

  22. msingh
    • 3 years ago
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    -root3/2 1/root2 root3/2

  23. ajprincess
    • 3 years ago
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    first two values are right. chck the last one

  24. msingh
    • 3 years ago
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    - root 3/2

  25. ajprincess
    • 3 years ago
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    nope. sin150=1/2.

  26. msingh
    • 3 years ago
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    okay

  27. ajprincess
    • 3 years ago
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    150=5pi/6

  28. ajprincess
    • 3 years ago
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    nw plug in those values and simplify

  29. msingh
    • 3 years ago
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    okay

  30. msingh
    • 3 years ago
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    i got (1/2root2)*(-root3-1)

  31. ajprincess
    • 3 years ago
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    yup right:)

  32. msingh
    • 3 years ago
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    @ajprincess thank you

  33. ajprincess
    • 3 years ago
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    welcome:)

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