Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\[\theta=\cos^{1}\frac{\sqrt3}{2}\] \[\cos\theta=\frac{\sqrt3}{2}\] So vat is the value of \(\theta\)? @msingh
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
cos60=1/2
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
well ya. but there is another value.
 one year ago

apple_pi Group TitleBest ResponseYou've already chosen the best response.1
why do you need to find theta? It's just cos(A+B)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
hw abt 5pi/6?
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
i mean cos(5pi/6)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\[\cos(\frac{5\pi}{6}+\frac{\pi}{4})=?\]
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
nw as @apple_pi mentioned u can use \(\cos(A+B)=\cos A\cos B\sin A\sin B\).
 one year ago

apple_pi Group TitleBest ResponseYou've already chosen the best response.1
@ajprincess why did you find theta? You could just leave it as acos(...), then cos(acos(...)) would cancel and then use pythagorus to find sin(acos(...))
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
well i found it easy to find theta first nd then do..:)
 one year ago

apple_pi Group TitleBest ResponseYou've already chosen the best response.1
ok whatever suits you :p
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
@ajprincess can u plse tell me exact answer
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
Well i am really sorry. I am nt supposed to give direct answers. pls check the code of conduct
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
dw:1367584877456:dw
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
plug in the values nd simplify
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
yes, after this, i m getting cos(5pi/6)sin(5pi/6)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
what is cos(pi/4)?
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
oh again i did wroong i place 1 as it is 1/ root2
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
what are cos(5pi/6),sin(pi/4) and sin(5pi/6)?
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
root3/2 1/root2 root3/2
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
first two values are right. chck the last one
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
nope. sin150=1/2.
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
150=5pi/6
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
nw plug in those values and simplify
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
i got (1/2root2)*(root31)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
yup right:)
 one year ago

msingh Group TitleBest ResponseYou've already chosen the best response.0
@ajprincess thank you
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
welcome:)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.