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cos60=1/2

well ya. but there is another value.

-cos30

why do you need to find theta?
It's just cos(A+B)

hw abt 5pi/6?

i mean cos(5pi/6)

okay

\[\cos(\frac{5\pi}{6}+\frac{\pi}{4})=?\]

nw as @apple_pi mentioned u can use \(\cos(A+B)=\cos A\cos B-\sin A\sin B\).

well i found it easy to find theta first nd then do..:)

ok whatever suits you :p

@ajprincess
can u plse tell me exact answer

Well i am really sorry. I am nt supposed to give direct answers. pls check the code of conduct

|dw:1367584877456:dw|

plug in the values nd simplify

yes, after this, i m getting
cos(5pi/6)-sin(5pi/6)

what is cos(pi/4)?

oh again i did wroong
i place 1 as it is 1/ root2

what are cos(5pi/6),sin(pi/4) and sin(5pi/6)?

-root3/2
1/root2
root3/2

first two values are right. chck the last one

- root 3/2

nope. sin150=1/2.

okay

150=5pi/6

nw plug in those values and simplify

okay

i got
(1/2root2)*(-root3-1)

yup right:)

@ajprincess
thank you

welcome:)