anonymous
  • anonymous
plse solve this
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ajprincess
  • ajprincess
\[\theta=\cos^{-1}\frac{-\sqrt3}{2}\] \[\cos\theta=\frac{-\sqrt3}{2}\] So vat is the value of \(\theta\)? @msingh
ajprincess
  • ajprincess
cos60=1/2
ajprincess
  • ajprincess
well ya. but there is another value.

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More answers

anonymous
  • anonymous
-cos30
anonymous
  • anonymous
why do you need to find theta? It's just cos(A+B)
ajprincess
  • ajprincess
hw abt 5pi/6?
ajprincess
  • ajprincess
i mean cos(5pi/6)
anonymous
  • anonymous
okay
ajprincess
  • ajprincess
\[\cos(\frac{5\pi}{6}+\frac{\pi}{4})=?\]
ajprincess
  • ajprincess
nw as @apple_pi mentioned u can use \(\cos(A+B)=\cos A\cos B-\sin A\sin B\).
anonymous
  • anonymous
@ajprincess why did you find theta? You could just leave it as acos(...), then cos(acos(...)) would cancel and then use pythagorus to find sin(acos(...))
ajprincess
  • ajprincess
well i found it easy to find theta first nd then do..:)
anonymous
  • anonymous
ok whatever suits you :p
anonymous
  • anonymous
@ajprincess can u plse tell me exact answer
ajprincess
  • ajprincess
Well i am really sorry. I am nt supposed to give direct answers. pls check the code of conduct
ajprincess
  • ajprincess
|dw:1367584877456:dw|
ajprincess
  • ajprincess
plug in the values nd simplify
anonymous
  • anonymous
yes, after this, i m getting cos(5pi/6)-sin(5pi/6)
ajprincess
  • ajprincess
what is cos(pi/4)?
anonymous
  • anonymous
oh again i did wroong i place 1 as it is 1/ root2
ajprincess
  • ajprincess
what are cos(5pi/6),sin(pi/4) and sin(5pi/6)?
anonymous
  • anonymous
-root3/2 1/root2 root3/2
ajprincess
  • ajprincess
first two values are right. chck the last one
anonymous
  • anonymous
- root 3/2
ajprincess
  • ajprincess
nope. sin150=1/2.
anonymous
  • anonymous
okay
ajprincess
  • ajprincess
150=5pi/6
ajprincess
  • ajprincess
nw plug in those values and simplify
anonymous
  • anonymous
okay
anonymous
  • anonymous
i got (1/2root2)*(-root3-1)
ajprincess
  • ajprincess
yup right:)
anonymous
  • anonymous
@ajprincess thank you
ajprincess
  • ajprincess
welcome:)

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