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msingh

plse solve this

  • 11 months ago
  • 11 months ago

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  1. ajprincess
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    \[\theta=\cos^{-1}\frac{-\sqrt3}{2}\] \[\cos\theta=\frac{-\sqrt3}{2}\] So vat is the value of \(\theta\)? @msingh

    • 11 months ago
  2. ajprincess
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    cos60=1/2

    • 11 months ago
  3. ajprincess
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    well ya. but there is another value.

    • 11 months ago
  4. msingh
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    -cos30

    • 11 months ago
  5. apple_pi
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    why do you need to find theta? It's just cos(A+B)

    • 11 months ago
  6. ajprincess
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    hw abt 5pi/6?

    • 11 months ago
  7. ajprincess
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    i mean cos(5pi/6)

    • 11 months ago
  8. msingh
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    okay

    • 11 months ago
  9. ajprincess
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    \[\cos(\frac{5\pi}{6}+\frac{\pi}{4})=?\]

    • 11 months ago
  10. ajprincess
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    nw as @apple_pi mentioned u can use \(\cos(A+B)=\cos A\cos B-\sin A\sin B\).

    • 11 months ago
  11. apple_pi
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    @ajprincess why did you find theta? You could just leave it as acos(...), then cos(acos(...)) would cancel and then use pythagorus to find sin(acos(...))

    • 11 months ago
  12. ajprincess
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    well i found it easy to find theta first nd then do..:)

    • 11 months ago
  13. apple_pi
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    ok whatever suits you :p

    • 11 months ago
  14. msingh
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    @ajprincess can u plse tell me exact answer

    • 11 months ago
  15. ajprincess
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    Well i am really sorry. I am nt supposed to give direct answers. pls check the code of conduct

    • 11 months ago
  16. ajprincess
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    |dw:1367584877456:dw|

    • 11 months ago
  17. ajprincess
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    plug in the values nd simplify

    • 11 months ago
  18. msingh
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    yes, after this, i m getting cos(5pi/6)-sin(5pi/6)

    • 11 months ago
  19. ajprincess
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    what is cos(pi/4)?

    • 11 months ago
  20. msingh
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    oh again i did wroong i place 1 as it is 1/ root2

    • 11 months ago
  21. ajprincess
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    what are cos(5pi/6),sin(pi/4) and sin(5pi/6)?

    • 11 months ago
  22. msingh
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    -root3/2 1/root2 root3/2

    • 11 months ago
  23. ajprincess
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    first two values are right. chck the last one

    • 11 months ago
  24. msingh
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    - root 3/2

    • 11 months ago
  25. ajprincess
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    nope. sin150=1/2.

    • 11 months ago
  26. msingh
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    okay

    • 11 months ago
  27. ajprincess
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    150=5pi/6

    • 11 months ago
  28. ajprincess
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    nw plug in those values and simplify

    • 11 months ago
  29. msingh
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    okay

    • 11 months ago
  30. msingh
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    i got (1/2root2)*(-root3-1)

    • 11 months ago
  31. ajprincess
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    yup right:)

    • 11 months ago
  32. msingh
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    @ajprincess thank you

    • 11 months ago
  33. ajprincess
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    welcome:)

    • 11 months ago
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