The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. Find the measure of the smaller angle. A. 18° B. 36° C. 54° D. 58°

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The sum of the measures of two complementary angles exceeds the difference of their measures by 72°. Find the measure of the smaller angle. A. 18° B. 36° C. 54° D. 58°

Geometry
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Let the angles be a and b. a+b=90( sum of complementary angles is 90) a+b-(a-b)=72 90-a+b=72 b-a=72-90 b-a=-18 a-b=18 a+b=90 Does that help?
This helps me a lot by the way.. :)
LOL

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@waterineyes reported for medal hounding! lol
he he :p
**whichever post of aj you see
now don't tell me you are not typing :P
good idea! ;)
well, no mods online, we can spam this question as much as we want :P
mods can see deleted comments.. -_-
i would look like a fool talking to myself xD
-_-
damn!
Let me tell you a fact., that 4th 'offline' person viewing this post is actually a moderator!
read my previous comment ;)
its evening here.
i know that its evening for all 4 of us
yup.
now, this is getting lamer :P
damn i missed your last comment :P
you cracking this joke since your OS birth.
that w is of lower caps , and name is in bold
i never said you are bad, at all
lets get back to helping.

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