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Brianna9898 Group Title

If the length of the beams is made six times the original length on each side, which statement is correct about the maximum area available for an exhibit to be displayed? It becomes 36 times the original area. It becomes 54 times the original area. It becomes 12 times the original area. It becomes 18 times the original area.

  • one year ago
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  1. Brianna9898 Group Title
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    Image>>>

    • one year ago
  2. Brianna9898 Group Title
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    SOMEONE HELLPPP!

    • one year ago
  3. Shadowys Group Title
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    the enlargement factor of area is the square of the enlargement factor of length. Do you need further help?

    • one year ago
  4. Brianna9898 Group Title
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    yes please

    • one year ago
  5. Shadowys Group Title
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    the enlargement factor in this case is 6. since \(A=l^2\) if l' = 6l, A'=36A.

    • one year ago
  6. Brianna9898 Group Title
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    so it would become 36 times the original area

    • one year ago
  7. Shadowys Group Title
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    yup! you've got it. :)

    • one year ago
  8. Brianna9898 Group Title
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    Okayyy, thank you so much!

    • one year ago
  9. Shadowys Group Title
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    you're welcome:)

    • one year ago
  10. Brianna9898 Group Title
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    can yu help me with another Qs?

    • one year ago
  11. Shadowys Group Title
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    sure, just post it outside so others can give it a go too.

    • one year ago
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