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anonymous
 3 years ago
If the length of the beams is made six times the original length on each side, which statement is correct about the maximum area available for an exhibit to be displayed?
It becomes 36 times the original area.
It becomes 54 times the original area.
It becomes 12 times the original area.
It becomes 18 times the original area.
anonymous
 3 years ago
If the length of the beams is made six times the original length on each side, which statement is correct about the maximum area available for an exhibit to be displayed? It becomes 36 times the original area. It becomes 54 times the original area. It becomes 12 times the original area. It becomes 18 times the original area.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the enlargement factor of area is the square of the enlargement factor of length. Do you need further help?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the enlargement factor in this case is 6. since \(A=l^2\) if l' = 6l, A'=36A.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so it would become 36 times the original area

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup! you've got it. :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okayyy, thank you so much!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can yu help me with another Qs?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sure, just post it outside so others can give it a go too.
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