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Brianna9898

  • one year ago

If the length of the beams is made six times the original length on each side, which statement is correct about the maximum area available for an exhibit to be displayed? It becomes 36 times the original area. It becomes 54 times the original area. It becomes 12 times the original area. It becomes 18 times the original area.

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  1. Brianna9898
    • one year ago
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    Image>>>

  2. Brianna9898
    • one year ago
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    SOMEONE HELLPPP!

  3. Shadowys
    • one year ago
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    the enlargement factor of area is the square of the enlargement factor of length. Do you need further help?

  4. Brianna9898
    • one year ago
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    yes please

  5. Shadowys
    • one year ago
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    the enlargement factor in this case is 6. since \(A=l^2\) if l' = 6l, A'=36A.

  6. Brianna9898
    • one year ago
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    so it would become 36 times the original area

  7. Shadowys
    • one year ago
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    yup! you've got it. :)

  8. Brianna9898
    • one year ago
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    Okayyy, thank you so much!

  9. Shadowys
    • one year ago
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    you're welcome:)

  10. Brianna9898
    • one year ago
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    can yu help me with another Qs?

  11. Shadowys
    • one year ago
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    sure, just post it outside so others can give it a go too.

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