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Brianna9898
 one year ago
If the length of the beams is made six times the original length on each side, which statement is correct about the maximum area available for an exhibit to be displayed?
It becomes 36 times the original area.
It becomes 54 times the original area.
It becomes 12 times the original area.
It becomes 18 times the original area.
Brianna9898
 one year ago
If the length of the beams is made six times the original length on each side, which statement is correct about the maximum area available for an exhibit to be displayed? It becomes 36 times the original area. It becomes 54 times the original area. It becomes 12 times the original area. It becomes 18 times the original area.

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Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1the enlargement factor of area is the square of the enlargement factor of length. Do you need further help?

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1the enlargement factor in this case is 6. since \(A=l^2\) if l' = 6l, A'=36A.

Brianna9898
 one year ago
Best ResponseYou've already chosen the best response.0so it would become 36 times the original area

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1yup! you've got it. :)

Brianna9898
 one year ago
Best ResponseYou've already chosen the best response.0Okayyy, thank you so much!

Brianna9898
 one year ago
Best ResponseYou've already chosen the best response.0can yu help me with another Qs?

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.1sure, just post it outside so others can give it a go too.
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