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Brianna9898

  • 2 years ago

If the length of the beams is made six times the original length on each side, which statement is correct about the maximum area available for an exhibit to be displayed? It becomes 36 times the original area. It becomes 54 times the original area. It becomes 12 times the original area. It becomes 18 times the original area.

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  1. Brianna9898
    • 2 years ago
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    Image>>>

  2. Brianna9898
    • 2 years ago
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    SOMEONE HELLPPP!

  3. Shadowys
    • 2 years ago
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    the enlargement factor of area is the square of the enlargement factor of length. Do you need further help?

  4. Brianna9898
    • 2 years ago
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    yes please

  5. Shadowys
    • 2 years ago
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    the enlargement factor in this case is 6. since \(A=l^2\) if l' = 6l, A'=36A.

  6. Brianna9898
    • 2 years ago
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    so it would become 36 times the original area

  7. Shadowys
    • 2 years ago
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    yup! you've got it. :)

  8. Brianna9898
    • 2 years ago
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    Okayyy, thank you so much!

  9. Shadowys
    • 2 years ago
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    you're welcome:)

  10. Brianna9898
    • 2 years ago
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    can yu help me with another Qs?

  11. Shadowys
    • 2 years ago
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    sure, just post it outside so others can give it a go too.

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