Brianna9898
If the length of the beams is made six times the original length on each side, which statement is correct about the maximum area available for an exhibit to be displayed?
It becomes 36 times the original area.
It becomes 54 times the original area.
It becomes 12 times the original area.
It becomes 18 times the original area.
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Brianna9898
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Image>>>
Brianna9898
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SOMEONE HELLPPP!
Shadowys
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the enlargement factor of area is the square of the enlargement factor of length.
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Brianna9898
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yes please
Shadowys
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the enlargement factor in this case is 6.
since \(A=l^2\)
if l' = 6l, A'=36A.
Brianna9898
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so it would become 36 times the original area
Shadowys
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yup! you've got it. :)
Brianna9898
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Okayyy, thank you so much!
Shadowys
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you're welcome:)
Brianna9898
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can yu help me with another Qs?
Shadowys
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sure, just post it outside so others can give it a go too.