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Sorry to ask a stupid question but in the second lecture (Kinematics) there was this equation (x = 8 - 6t + t2) and i never studied this before, could some one explain how to solve this, Thank you

MIT 8.01 Physics I Classical Mechanics, Fall 1999
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x is the displacement. it is given as a function of time 't'. now velocity v=dx/dt differentiate the given function w.r.t time, you will get the velocity. if you need to find acceleration, differentiate it again.
Do you know derive? If not tell me I teach you the simpliest way.
It's not stupid. You don't know unless you ask or try. One of the 2. Either experience it, or learn from someone who has. That is my best advice.

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Other answers:

we have displacement as function of time \[x = 8 - 6t + t^2 \] and when you differentiate it, you get \[frac{dx}{dt} = -6 + 2t = v \] and when you differentiate it again you get \[frac{dv}{dt} = 2 = a \] a is acceleration and v is velocity, here you have simple derivatives like \[frac{d(x^2)}{dx} = 2x \] etc...
sorry for my math formula bad writing, i am not familiar with this syntax (this is not latex ?) :) frac is just a fraction

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