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since \(A=l^2\) and \(A'=l'^2\)
when \(A=9A'\)
sub them in to get the relationship between l and l'

what am i supposed to sub in?

the l and l '
like this:
\(A=9A'\)
\(l^2 = 9 l'^2\)

im like really slow and have no idea wut im doing.-_-

sorry im back and thank you.

Getting ?? @Brianna9898

I have no idea!

Are you getting till here"
\[l_2^2=9 l_1^2\]

why is there a 1 & 2 at the bottom

... and how am I supposed to square root an l ??

Oh that..
\(l_1\) is showing length of first square.
\(l_2\) is for length of second square.

you can actually..
See,
What is square root of this:
\[\large \sqrt{2^2} = ??\]

Similar way what will be square root of this:
\[\large \sqrt{l_2^2} = ??\]

\[l\]

??

Or you can say \(l_2\)..
Good..

Similarly can you tell for:
\[\large \sqrt{9l_1^2} = ??\]

so you have to keep the 2 at the bottom

so it would be \[9l _{1} ??\]

You forgot to take square root of 9.
\(l_1\0 is good though..

What is square root of 9?

Yep after square root you will get like:
\[\large l_2 = 3 \times l_1\]

So, which answer choice is this?

the first one?

Well Done...

yayyy! thank you guys for helping me!

I don't even know how to give a medal on this thing

Are you seeing best response after shadows post ?/
Just click that..

oh okay, can I give a medal to two ppl?

No, just only one..

On one post you can give medal to one only..