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Brianna9898
 2 years ago
A floor has two squareshaped designs. The area of the second squareshaped design is nine times greater than the area of the first squareshaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?
Brianna9898
 2 years ago
A floor has two squareshaped designs. The area of the second squareshaped design is nine times greater than the area of the first squareshaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?

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Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0these are the options... The length of the side of the second square is 3 times greater than the length of the side of the first square. The length of the side of the second square is 12 times greater than the length of the side of the first square. The length of the side of the second square is 9 times greater than the length of the side of the first square. The length of the side of the second square is 6 times greater than the length of the side of the first square.

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.2since \(A=l^2\) and \(A'=l'^2\) when \(A=9A'\) sub them in to get the relationship between l and l'

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0what am i supposed to sub in?

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.2the l and l ' like this: \(A=9A'\) \(l^2 = 9 l'^2\)

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0im like really slow and have no idea wut im doing._

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.2lol. i guess i'll try to do it step by step. since \(A=l^2\), \(A_1=l_1^2\) (this is the first square)............(1) \(A_2=l_2^2\) (this is the second square)........(2) since the area of the second square is nine times the first, (it's the only given condition, so we start from that.) \(A_2=9A_1\) subbing (1) and (2) into it, we get, \(l_2^2=9l_1^2\) what did you get after taking thesquare roots of both sides?

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0sorry im back and thank you.

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Just take the square root both the sides and tell us what you got as @Shadowys said above..

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Getting ?? @Brianna9898

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Are you getting till here" \[l_2^2=9 l_1^2\]

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0why is there a 1 & 2 at the bottom

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1See when you will take square root you will get like: \[\large \sqrt{l_2^2} = \sqrt{9 l_1^2}\] Can you tell what is this: \[\large \sqrt{l_2^2} = ??\]

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0... and how am I supposed to square root an l ??

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Oh that.. \(l_1\) is showing length of first square. \(l_2\) is for length of second square.

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1you can actually.. See, What is square root of this: \[\large \sqrt{2^2} = ??\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Similar way what will be square root of this: \[\large \sqrt{l_2^2} = ??\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Or you can say \(l_2\).. Good..

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Similarly can you tell for: \[\large \sqrt{9l_1^2} = ??\]

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0so you have to keep the 2 at the bottom

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.2the one and two are sub scripts to differentiate between the first length and the second, thus, 1 and 2 respectively.

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1see, 1 and 2 is differentiating lengths of the two square you are given with, so don't think here of just l think here of \(l_1\) and \(l_2\)..

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0so it would be \[9l _{1} ??\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1You forgot to take square root of 9. \(l_1\0 is good though..

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1What is square root of 9?

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Yep after square root you will get like: \[\large l_2 = 3 \times l_1\]

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1So, which answer choice is this?

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1And give all the thanks to @Shadowys

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0yayyy! thank you guys for helping me!

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0I don't even know how to give a medal on this thing

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1Are you seeing best response after shadows post ?/ Just click that..

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0oh okay, can I give a medal to two ppl?

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1No, just only one..

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.1On one post you can give medal to one only..

Brianna9898
 2 years ago
Best ResponseYou've already chosen the best response.0thanx for the medal @Shadowys !
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