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Brianna9898

  • 2 years ago

A floor has two square-shaped designs. The area of the second square-shaped design is nine times greater than the area of the first square-shaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?

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  1. Brianna9898
    • 2 years ago
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    these are the options... The length of the side of the second square is 3 times greater than the length of the side of the first square. The length of the side of the second square is 12 times greater than the length of the side of the first square. The length of the side of the second square is 9 times greater than the length of the side of the first square. The length of the side of the second square is 6 times greater than the length of the side of the first square.

  2. Shadowys
    • 2 years ago
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    since \(A=l^2\) and \(A'=l'^2\) when \(A=9A'\) sub them in to get the relationship between l and l'

  3. Brianna9898
    • 2 years ago
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    what am i supposed to sub in?

  4. Shadowys
    • 2 years ago
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    the l and l ' like this: \(A=9A'\) \(l^2 = 9 l'^2\)

  5. Brianna9898
    • 2 years ago
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    im like really slow and have no idea wut im doing.-_-

  6. Shadowys
    • 2 years ago
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    lol. i guess i'll try to do it step by step. since \(A=l^2\), \(A_1=l_1^2\) (this is the first square)............(1) \(A_2=l_2^2\) (this is the second square)........(2) since the area of the second square is nine times the first, (it's the only given condition, so we start from that.) \(A_2=9A_1\) subbing (1) and (2) into it, we get, \(l_2^2=9l_1^2\)| what did you get after taking thesquare roots of both sides?

  7. Brianna9898
    • 2 years ago
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    sorry im back and thank you.

  8. waterineyes
    • 2 years ago
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    Just take the square root both the sides and tell us what you got as @Shadowys said above..

  9. waterineyes
    • 2 years ago
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    Getting ?? @Brianna9898

  10. Brianna9898
    • 2 years ago
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    I have no idea!

  11. waterineyes
    • 2 years ago
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    Are you getting till here" \[l_2^2=9 l_1^2\]

  12. Brianna9898
    • 2 years ago
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    why is there a 1 & 2 at the bottom

  13. waterineyes
    • 2 years ago
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    See when you will take square root you will get like: \[\large \sqrt{l_2^2} = \sqrt{9 l_1^2}\] Can you tell what is this: \[\large \sqrt{l_2^2} = ??\]

  14. Brianna9898
    • 2 years ago
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    ... and how am I supposed to square root an l ??

  15. waterineyes
    • 2 years ago
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    Oh that.. \(l_1\) is showing length of first square. \(l_2\) is for length of second square.

  16. waterineyes
    • 2 years ago
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    you can actually.. See, What is square root of this: \[\large \sqrt{2^2} = ??\]

  17. Brianna9898
    • 2 years ago
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    2

  18. waterineyes
    • 2 years ago
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    Similar way what will be square root of this: \[\large \sqrt{l_2^2} = ??\]

  19. Brianna9898
    • 2 years ago
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    \[l\]

  20. Brianna9898
    • 2 years ago
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    ??

  21. waterineyes
    • 2 years ago
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    Or you can say \(l_2\).. Good..

  22. waterineyes
    • 2 years ago
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    Similarly can you tell for: \[\large \sqrt{9l_1^2} = ??\]

  23. Brianna9898
    • 2 years ago
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    so you have to keep the 2 at the bottom

  24. Shadowys
    • 2 years ago
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    the one and two are sub scripts to differentiate between the first length and the second, thus, 1 and 2 respectively.

  25. waterineyes
    • 2 years ago
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    see, 1 and 2 is differentiating lengths of the two square you are given with, so don't think here of just l think here of \(l_1\) and \(l_2\)..

  26. Brianna9898
    • 2 years ago
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    so it would be \[9l _{1} ??\]

  27. waterineyes
    • 2 years ago
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    You forgot to take square root of 9. \(l_1\0 is good though..

  28. waterineyes
    • 2 years ago
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    What is square root of 9?

  29. Brianna9898
    • 2 years ago
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    3

  30. waterineyes
    • 2 years ago
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    Yep after square root you will get like: \[\large l_2 = 3 \times l_1\]

  31. waterineyes
    • 2 years ago
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    So, which answer choice is this?

  32. Brianna9898
    • 2 years ago
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    the first one?

  33. waterineyes
    • 2 years ago
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    Well Done...

  34. waterineyes
    • 2 years ago
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    And give all the thanks to @Shadowys

  35. Brianna9898
    • 2 years ago
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    yayyy! thank you guys for helping me!

  36. Brianna9898
    • 2 years ago
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    I don't even know how to give a medal on this thing

  37. waterineyes
    • 2 years ago
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    Are you seeing best response after shadows post ?/ Just click that..

  38. Brianna9898
    • 2 years ago
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    oh okay, can I give a medal to two ppl?

  39. waterineyes
    • 2 years ago
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    No, just only one..

  40. waterineyes
    • 2 years ago
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    On one post you can give medal to one only..

  41. Brianna9898
    • 2 years ago
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    thanx for the medal @Shadowys !

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