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Brianna9898 Group Title

A floor has two square-shaped designs. The area of the second square-shaped design is nine times greater than the area of the first square-shaped design. Which statement gives the correct relationship between the lengths of the sides of the two squares?

  • one year ago
  • one year ago

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  1. Brianna9898 Group Title
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    these are the options... The length of the side of the second square is 3 times greater than the length of the side of the first square. The length of the side of the second square is 12 times greater than the length of the side of the first square. The length of the side of the second square is 9 times greater than the length of the side of the first square. The length of the side of the second square is 6 times greater than the length of the side of the first square.

    • one year ago
  2. Shadowys Group Title
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    since \(A=l^2\) and \(A'=l'^2\) when \(A=9A'\) sub them in to get the relationship between l and l'

    • one year ago
  3. Brianna9898 Group Title
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    what am i supposed to sub in?

    • one year ago
  4. Shadowys Group Title
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    the l and l ' like this: \(A=9A'\) \(l^2 = 9 l'^2\)

    • one year ago
  5. Brianna9898 Group Title
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    im like really slow and have no idea wut im doing.-_-

    • one year ago
  6. Shadowys Group Title
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    lol. i guess i'll try to do it step by step. since \(A=l^2\), \(A_1=l_1^2\) (this is the first square)............(1) \(A_2=l_2^2\) (this is the second square)........(2) since the area of the second square is nine times the first, (it's the only given condition, so we start from that.) \(A_2=9A_1\) subbing (1) and (2) into it, we get, \(l_2^2=9l_1^2\)| what did you get after taking thesquare roots of both sides?

    • one year ago
  7. Brianna9898 Group Title
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    sorry im back and thank you.

    • one year ago
  8. waterineyes Group Title
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    Just take the square root both the sides and tell us what you got as @Shadowys said above..

    • one year ago
  9. waterineyes Group Title
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    Getting ?? @Brianna9898

    • one year ago
  10. Brianna9898 Group Title
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    I have no idea!

    • one year ago
  11. waterineyes Group Title
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    Are you getting till here" \[l_2^2=9 l_1^2\]

    • one year ago
  12. Brianna9898 Group Title
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    why is there a 1 & 2 at the bottom

    • one year ago
  13. waterineyes Group Title
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    See when you will take square root you will get like: \[\large \sqrt{l_2^2} = \sqrt{9 l_1^2}\] Can you tell what is this: \[\large \sqrt{l_2^2} = ??\]

    • one year ago
  14. Brianna9898 Group Title
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    ... and how am I supposed to square root an l ??

    • one year ago
  15. waterineyes Group Title
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    Oh that.. \(l_1\) is showing length of first square. \(l_2\) is for length of second square.

    • one year ago
  16. waterineyes Group Title
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    you can actually.. See, What is square root of this: \[\large \sqrt{2^2} = ??\]

    • one year ago
  17. Brianna9898 Group Title
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    2

    • one year ago
  18. waterineyes Group Title
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    Similar way what will be square root of this: \[\large \sqrt{l_2^2} = ??\]

    • one year ago
  19. Brianna9898 Group Title
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    \[l\]

    • one year ago
  20. Brianna9898 Group Title
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    ??

    • one year ago
  21. waterineyes Group Title
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    Or you can say \(l_2\).. Good..

    • one year ago
  22. waterineyes Group Title
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    Similarly can you tell for: \[\large \sqrt{9l_1^2} = ??\]

    • one year ago
  23. Brianna9898 Group Title
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    so you have to keep the 2 at the bottom

    • one year ago
  24. Shadowys Group Title
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    the one and two are sub scripts to differentiate between the first length and the second, thus, 1 and 2 respectively.

    • one year ago
  25. waterineyes Group Title
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    see, 1 and 2 is differentiating lengths of the two square you are given with, so don't think here of just l think here of \(l_1\) and \(l_2\)..

    • one year ago
  26. Brianna9898 Group Title
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    so it would be \[9l _{1} ??\]

    • one year ago
  27. waterineyes Group Title
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    You forgot to take square root of 9. \(l_1\0 is good though..

    • one year ago
  28. waterineyes Group Title
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    What is square root of 9?

    • one year ago
  29. Brianna9898 Group Title
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    3

    • one year ago
  30. waterineyes Group Title
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    Yep after square root you will get like: \[\large l_2 = 3 \times l_1\]

    • one year ago
  31. waterineyes Group Title
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    So, which answer choice is this?

    • one year ago
  32. Brianna9898 Group Title
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    the first one?

    • one year ago
  33. waterineyes Group Title
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    Well Done...

    • one year ago
  34. waterineyes Group Title
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    And give all the thanks to @Shadowys

    • one year ago
  35. Brianna9898 Group Title
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    yayyy! thank you guys for helping me!

    • one year ago
  36. Brianna9898 Group Title
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    I don't even know how to give a medal on this thing

    • one year ago
  37. waterineyes Group Title
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    Are you seeing best response after shadows post ?/ Just click that..

    • one year ago
  38. Brianna9898 Group Title
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    oh okay, can I give a medal to two ppl?

    • one year ago
  39. waterineyes Group Title
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    No, just only one..

    • one year ago
  40. waterineyes Group Title
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    On one post you can give medal to one only..

    • one year ago
  41. Brianna9898 Group Title
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    thanx for the medal @Shadowys !

    • one year ago
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