## A community for students. Sign up today

Here's the question you clicked on:

## ladiesman217 3 years ago medals and fans rewarded

• This Question is Closed
1. ladiesman217

$3x^2=33x+24$

2. ladiesman217

@ajprincess @nubeer @.Sam. can you help me please

3. ajprincess

$$3x^2=33x+24$$ $$3x^2-33x+24=0$$ Use quadratic formula. $x=\frac{ -b\pm\sqrt{b^2-4ac} }{ 2a }$ the values of a, b and c can be found by comparing the equation $$3x^2-33x+24=0$$ with the general equation $$ax^2+bx+c=0$$. Does that help? @ladiesman217

4. ladiesman217

ya

5. anonymous

**-24 dividing the entire equation by 3 would simplify calculations

6. ajprincess

it is actually $$3x^2-33x-24=0$$. am sorry abt the mistake

7. ajprincess

ya. first factor out 3 and then divide by 3 both sides. After that use quadratic formula:)

8. ladiesman217

the equation i got was$\frac{ -(-3)\sqrt{3^{2}-4(3)(-24)} }{ 2*3 }$

9. ajprincess

b=-33

10. ladiesman217

this is the correct equation right $\frac{ -(-33)\sqrt{-33^{2}-4(3)(-24)} }{ 2*3 }$

11. ajprincess

it will be $\frac{ -(-33)\sqrt{(-33)^2-4*3*(-24)} }{ 2*3}$

12. ladiesman217

i got$\frac{ 11\pm \sqrt{153} }{ 2 }$

13. ajprincess

ya right:)

14. ajprincess

good work:)

15. ladiesman217

thnx

16. ajprincess

welcome:)

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy