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ladiesman217
 2 years ago
medals and fans rewarded
ladiesman217
 2 years ago
medals and fans rewarded

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ladiesman217
 2 years ago
Best ResponseYou've already chosen the best response.0@ajprincess @nubeer @.Sam. can you help me please

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.2\(3x^2=33x+24\) \(3x^233x+24=0\) Use quadratic formula. \[x=\frac{ b\pm\sqrt{b^24ac} }{ 2a }\] the values of a, b and c can be found by comparing the equation \(3x^233x+24=0\) with the general equation \(ax^2+bx+c=0\). Does that help? @ladiesman217

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.1**24 dividing the entire equation by 3 would simplify calculations

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.2it is actually \(3x^233x24=0\). am sorry abt the mistake

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.2ya. first factor out 3 and then divide by 3 both sides. After that use quadratic formula:)

ladiesman217
 2 years ago
Best ResponseYou've already chosen the best response.0the equation i got was\[\frac{ (3)\sqrt{3^{2}4(3)(24)} }{ 2*3 }\]

ladiesman217
 2 years ago
Best ResponseYou've already chosen the best response.0this is the correct equation right \[\frac{ (33)\sqrt{33^{2}4(3)(24)} }{ 2*3 }\]

ajprincess
 2 years ago
Best ResponseYou've already chosen the best response.2it will be \[\frac{ (33)\sqrt{(33)^24*3*(24)} }{ 2*3}\]

ladiesman217
 2 years ago
Best ResponseYou've already chosen the best response.0i got\[\frac{ 11\pm \sqrt{153} }{ 2 }\]
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