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ladiesman217 Group TitleBest ResponseYou've already chosen the best response.0
\[3x^2=33x+24\]
 one year ago

ladiesman217 Group TitleBest ResponseYou've already chosen the best response.0
@ajprincess @nubeer @.Sam. can you help me please
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
\(3x^2=33x+24\) \(3x^233x+24=0\) Use quadratic formula. \[x=\frac{ b\pm\sqrt{b^24ac} }{ 2a }\] the values of a, b and c can be found by comparing the equation \(3x^233x+24=0\) with the general equation \(ax^2+bx+c=0\). Does that help? @ladiesman217
 one year ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.1
**24 dividing the entire equation by 3 would simplify calculations
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
it is actually \(3x^233x24=0\). am sorry abt the mistake
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
ya. first factor out 3 and then divide by 3 both sides. After that use quadratic formula:)
 one year ago

ladiesman217 Group TitleBest ResponseYou've already chosen the best response.0
the equation i got was\[\frac{ (3)\sqrt{3^{2}4(3)(24)} }{ 2*3 }\]
 one year ago

ladiesman217 Group TitleBest ResponseYou've already chosen the best response.0
this is the correct equation right \[\frac{ (33)\sqrt{33^{2}4(3)(24)} }{ 2*3 }\]
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
it will be \[\frac{ (33)\sqrt{(33)^24*3*(24)} }{ 2*3}\]
 one year ago

ladiesman217 Group TitleBest ResponseYou've already chosen the best response.0
i got\[\frac{ 11\pm \sqrt{153} }{ 2 }\]
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
ya right:)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
good work:)
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.2
welcome:)
 one year ago
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