ValentinaT
Help with geometry/rational expressions?



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ValentinaT
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SerikMB
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the height of the triangle is 2?

ValentinaT
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Okay.

SerikMB
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x/x^2+2x=1/x+1

ValentinaT
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Is that the rational expression in simplified form?

SerikMB
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1/(x+2)

SerikMB
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\[\frac{ Area of \triangle }{ Area of rectangle }\]

SerikMB
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Atriangle=x*2/2=x
Arectangle=x*(x+2)=x^2+2x

ValentinaT
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I'm sorry, I'm still confused, could you help me put all this together so I might understand better? Sorry, if I'm asking too much of you.

SerikMB
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do you have answers?

ValentinaT
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To the area of triangle over area of rectangle? No.

SerikMB
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yes

SerikMB
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because it is inside the rectangle

ValentinaT
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\[\frac{ area of \triangle }{ area of rectangle }\] = \[\frac{ x(2)/2 }{ x(x+2) } = \frac{ x }{ x^2 + 2x }\]