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joemagee Group Title

7/8 times 39/180 and simplify. I keep getting 273/1440 but it's telling me I'm wrong.

  • one year ago
  • one year ago

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  1. jdoe0001 Group Title
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    it's correct :), you just need to SIMPLIFY it :)

    • one year ago
  2. joemagee Group Title
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    How?

    • one year ago
  3. jdoe0001 Group Title
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    do you know what simplifying means?

    • one year ago
  4. joemagee Group Title
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    Sometimes. (-:. I guess I should divide 273 by 1440. Is that right?

    • one year ago
  5. jdoe0001 Group Title
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    well, yes and no, you should to the extent you're still left with a fraction, so, \(\cfrac{2}{4} \ simplifies\ to\ \cfrac{1}{2}\)

    • one year ago
  6. Naveen Group Title
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    Ok, so that was easy. But I cant think of where to start. 273 is a large number as is 1440. Is there a trick?

    • one year ago
  7. jdoe0001 Group Title
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    so \(\cfrac{1}{2}\times 2 = \cfrac{2}{4}\), same proportions, with just a multiplier, in this case "2"

    • one year ago
  8. jdoe0001 Group Title
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    well, sorta, 273, 2+7+3 =12, 12 is divisible by 3, start from there, divide both by 3 :), see if that works

    • one year ago
  9. Naveen Group Title
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    Suppose it was 123/457?

    • one year ago
  10. jdoe0001 Group Title
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    well, then I'd check what I can get from the numbers, usually you start small, 2, or 3, or 4 and so on, the smallest integer you can divide, NOT 1 of course, so 2 and so on, yo have 273, is not divisible by 2, so I checked with 3 :)

    • one year ago
  11. jdoe0001 Group Title
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    let me see if I can make a quick table of both of those numbers, simplifying

    • one year ago
  12. jdoe0001 Group Title
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    • one year ago
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