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@jim_thompson5910 @Mertsj help pls

umm im pretty sure ADC is 180. Why wouldnt it be?

since I saw (theta) symbol at ADB and you indicate about ADC is theta

im sorry ADB is theta :P

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\[c^2=m^2+(\frac{b}{2})^2-2m(\frac{b}{2})\cos \theta \]

Solve for cos theta

ok yea i proved that part

and cos(180-theta)
is putting a negative sign infront of that equation

how can we prove part b though?

- 4m^2 + b^2 - 4c^2 / 4mb = 4m^2 + b^2 - 4a^2 / 4mb
right?

ok i solved it thank you