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onegirl
Group Title
Find the function f(x) satisfying the given conditions. (HINT: You are finding the value of C)
 one year ago
 one year ago
onegirl Group Title
Find the function f(x) satisfying the given conditions. (HINT: You are finding the value of C)
 one year ago
 one year ago

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myininaya Group TitleBest ResponseYou've already chosen the best response.1
Find \[\int\limits_{}^{}f'(x) dx=f(x)+C, \text{ where } (f)'=f'\]
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Or evaluate
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Integrate the function given to get from f' to f.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Don't forget when you integrate, put +C.
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.1
can u explain? :/
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{}^{}f'(x) dx=\int\limits_{}^{}(4x^21) dx\] You may find it easy to use the following: \[\int\limits_{}^{}x^n dx =\frac{x^{n+1}}{n+1}+C, n \neq 1\] This is because \[(\frac{x^{n+1}}{n+1})'=(n+1) \cdot \frac{x^{n+11}}{n+1}=x^{n+11}=x^n\] And you may also want to use \[\int\limits_{}^{}k dx=kx+C \text{ where} K, C \text{ are a constant} \]
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
This is because (kx+C)'=(kx)'+(C)'=k(x)'+0+k(x)'=k(1)=k
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.1
okay thanks
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Are you familiar with the idea of `Integration` yet? Or has it only been introduced to you as the process of finding the `antiderivative` so far?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.1
no i'm not familiar
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.1
@Best_Mathematician can u help?
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
dw:1367625325100:dw
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
so, when you have f' (4x^2 +1) take integral to get back the original function. . when take integral, the solution for that method always a family solution. in case they give you the special solution, that means they want you to pick out just special C in set of family solution . take integral of f' you have f(x) = 4x^3/3 x +C and when they give you f(0) =2 just plug 0 into the function you' ve just got. to find C f(0) = 4 *0^3/3 0 +C = 2 > C =2 that's it
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
sorry , one more step. plug C back to f(x) = 4x^3/3  x +2
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
I 'm supper dummy at teaching, hope you can understand what i mean
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.1
so plugging 2 back into f(x) = 4x^3/3  x + 2 right?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.1
i got 32/3 or 10.6666
 one year ago

Loser66 Group TitleBest ResponseYou've already chosen the best response.0
hey, you misunderstand the concept, they ask you to find out C, and you got C =2 that's it. just plug C =2 into the function, nothing to do more.
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.1
ohh okay my bad
 one year ago
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