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Use distance formula.

I don't see how that would help

|dw:1367651958829:dw|

How it would help is because of the properties of parallelograms.

I kinda see what you're saying, but this section is on vectors

This is what my prof. put as the answer
ABCD is a Parrallogram if vector AB+VECTOR AD=VECTOR AC

Well, in this case, it isn't but... let me see.... I may have an easy reference already made.

right, for this problem the answer is that it isn't a Parrallogram

OK, this was a draft, but it has it in there.

OOOOO

Yah, I know, most people don't have a rough draft of vector additon sitting around in a PDF. LOL.

|dw:1367653361531:dw|

YES!

or u can do it thru dot produts and see the angles inbetween match up or not

Brilliant! Thanks! :)
Is there a way for me to save this conversation

/nod /nod Which might be a better test for random points.

Interesting, i didn't even think of applying the dot product

also another way

Oh no! It is math! There is more than one way to skin a math problem! Hehe.

|dw:1367653577281:dw|

just giving u a couple solutions cuz i dunno if u learnt the proof for cross product area yet

basically it has to do with |dw:1367653732887:dw|

just watch the lecture, if u are interested in how its proved

I definitely will

18.02 lecture 2 i think

Okay, thanks again!

your welcome man, have a good one

Have fun!