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hunter111 Group Title

Given: points A(2; 1), B(3; 2), C(4; 4) andD(5; 2). IsABCDa parallelogram

  • one year ago
  • one year ago

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  1. goformit100 Group Title
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    Use distance formula.

    • one year ago
  2. hunter111 Group Title
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    I don't see how that would help

    • one year ago
  3. goformit100 Group Title
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    |dw:1367651958829:dw|

    • one year ago
  4. e.mccormick Group Title
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    How it would help is because of the properties of parallelograms.

    • one year ago
  5. e.mccormick Group Title
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    What goformit100 is talking about should be somewhere in your book. A list of information like this one: http://www.regentsprep.org/Regents/math/geometry/GP9/LParallelogram.htm

    • one year ago
  6. hunter111 Group Title
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    I kinda see what you're saying, but this section is on vectors

    • one year ago
  7. alicealc Group Title
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    if vector AB = vector DC and vector AD = vector BC, then it's a parallelogram. vector AB = point B - point A

    • one year ago
  8. hunter111 Group Title
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    This is what my prof. put as the answer ABCD is a Parrallogram if vector AB+VECTOR AD=VECTOR AC

    • one year ago
  9. e.mccormick Group Title
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    AH, in vectors. OK, yes, if they define the sides of the parallelogram. So if you can prove that they are one vector added on to the other, and vice verca, then they define it.

    • one year ago
  10. hunter111 Group Title
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    I'm on the verge of seeing what you're saying. But, I don't see how proving that by proving that when we add 2 of the vectors it equals the 3rd one (which is given), indicates that the set of given points is a Parrallogram.

    • one year ago
  11. e.mccormick Group Title
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    Well, in this case, it isn't but... let me see.... I may have an easy reference already made.

    • one year ago
  12. hunter111 Group Title
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    right, for this problem the answer is that it isn't a Parrallogram

    • one year ago
  13. e.mccormick Group Title
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    OK, this was a draft, but it has it in there.

    • one year ago
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  14. e.mccormick Group Title
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    If you look at the first page, the vectors can add up on either side to meet at the far corner. In this problem of yours, they add one way, but not the other. Well, they don't reach one of the points through addition.

    • one year ago
  15. hunter111 Group Title
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    OOOOO

    • one year ago
  16. e.mccormick Group Title
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    Yah, I know, most people don't have a rough draft of vector additon sitting around in a PDF. LOL.

    • one year ago
  17. hunter111 Group Title
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    so if we have to vectors and add them they form Parrallogram no matter what. But this problem is asking specifically if the Parrallogram they form has a vertices on the indicated points? essentially

    • one year ago
  18. dan815 Group Title
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    |dw:1367653361531:dw|

    • one year ago
  19. e.mccormick Group Title
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    YES!

    • one year ago
  20. dan815 Group Title
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    or u can do it thru dot produts and see the angles inbetween match up or not

    • one year ago
  21. hunter111 Group Title
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    Brilliant! Thanks! :) Is there a way for me to save this conversation

    • one year ago
  22. e.mccormick Group Title
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    /nod /nod Which might be a better test for random points.

    • one year ago
  23. hunter111 Group Title
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    Interesting, i didn't even think of applying the dot product

    • one year ago
  24. dan815 Group Title
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    also another way

    • one year ago
  25. e.mccormick Group Title
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    Oh no! It is math! There is more than one way to skin a math problem! Hehe.

    • one year ago
  26. dan815 Group Title
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    |dw:1367653577281:dw|

    • one year ago
  27. dan815 Group Title
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    just giving u a couple solutions cuz i dunno if u learnt the proof for cross product area yet

    • one year ago
  28. dan815 Group Title
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    check out the MIT 18.02 first or 2nd lecture for a nice explaination of cross product area and its proof

    • one year ago
  29. e.mccormick Group Title
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    I was also thinking if they formed a basis for the span of linar combinations it could also be an indicator.... but they might not be parts of the same parallelogram and still have that be true.

    • one year ago
  30. dan815 Group Title
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    basically it has to do with |dw:1367653732887:dw|

    • one year ago
  31. dan815 Group Title
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    just watch the lecture, if u are interested in how its proved

    • one year ago
  32. hunter111 Group Title
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    I definitely will

    • one year ago
  33. dan815 Group Title
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    18.02 lecture 2 i think

    • one year ago
  34. dan815 Group Title
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    in simple 2D terms, cross product is basically like applying the dotproduct for the new rotated vector now that the angle between them is 90-theta and inbetween them

    • one year ago
  35. hunter111 Group Title
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    Okay, thanks again!

    • one year ago
  36. dan815 Group Title
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    your welcome man, have a good one

    • one year ago
  37. e.mccormick Group Title
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    Have fun!

    • one year ago
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is replying to Can someone tell me what button the professor is hitting...

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