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Jash298
Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25. If x represents the smallest integer, then which equation could be used to solve the problem? Take me through the steps on solving this dont give me the answer trying to understand how to do this x+1,x something like x+1+25??
if the first odd number is x, then consecutive odd numbers can be found by adding two to the previous one.thus the three consecutive odd numbers will be x, x+2,x+4 the largest of the three will be x+4. twice of the smallest will be 2x. it is given that their sum is 25. so x+4+2x=25 Does that help?
hmm. which part of my answer is nt clear to u? @Jash298
adding two to the previous one?? Where did x+2,x+4 come from
1 is an odd number right? what is the next odd number after 1?
You used n+2,n+4 to represent the odd integer.am I catching on?
Would it be the same if it were a even number? n+2,N+4?
I get how you worked it out and that turned out as your answer.I just dont know how to evaluate these problems I need to work on it
if the smallest even number is n, then the next two even numbers will be n+2 and n+4.
This was a easy problem and took me long to figure it out ._. thanks..
it will be easy for u to assume numbers nd then find a relation
welcome:) trying out some more similar questions will give u more practice:)