haleyking345
Write the standard form of the equation of each circle described.
a.) center at (0,0), radius 3 Square root 3



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haleyking345
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dw:1367681738477:dw

tcarroll010
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The equation (for circles at the center) in general is:
x^2 + y^2 = r^2
All you have to do is substitute in for the "r".

haleyking345
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3 square root of 3 squared. What would that equal?

tcarroll010
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(3^2)(sqrt(3))^2

rman3
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The standard form is x^2 + y^2 = r^2
3sqrt3 is equal to 27. Square the 3, which is 9. Then the sqrt of 3 which is just 3.

tcarroll010
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So, (9)(sqrt(3))^2

rman3
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Since the center is at 0,0 you don't need to change the x2 or y2

tcarroll010
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And (sqrt(3))^2 = 3

tcarroll010
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so, (3)^2 x (sqrt(3))^2 = 9 x 3 = 27

haleyking345
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ok, that makes perfect sense. Thank you so much!!!!

tcarroll010
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So, you have:
x^2 + y^2 = (3 x sqrt(3))^2
x^2 + y^2 = 27

tcarroll010
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Good luck in all of your studies and thx for the recognition! @haleyking345