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BrainsNThings

  • 3 years ago

Solve for x, Show your work

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  1. BrainsNThings
    • 3 years ago
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    \[\sqrt{x+2}+4=x\]

  2. ajprincess
    • 3 years ago
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    The first step u have to do in problems like this is to get rid of the sqrt. this can be done by squaring both sides. \(\sqrt{x+2}+4=x\) \(\sqrt{x+2}=x-4\) \((\sqrt{x+2})^2=(x-4)^2\) \(x+2=x^2-8x+16\) \(x^2-8x-x+16-2=0\) \(x^2-9x+14=0\) Use quadratic formula to find x. \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] the values of a, b nd c can be found by comparing the equation \(x^2-9x+14=0\) with the general equation \(ax62+bx+c=0\). Does that help? @BrainsNThings

  3. ajprincess
    • 3 years ago
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    *\(ax^2+bx+c=0\)

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