## BrainsNThings Group Title Solve for x, Show your work one year ago one year ago

1. BrainsNThings Group Title

$\sqrt{x+2}+4=x$

2. ajprincess Group Title

The first step u have to do in problems like this is to get rid of the sqrt. this can be done by squaring both sides. $$\sqrt{x+2}+4=x$$ $$\sqrt{x+2}=x-4$$ $$(\sqrt{x+2})^2=(x-4)^2$$ $$x+2=x^2-8x+16$$ $$x^2-8x-x+16-2=0$$ $$x^2-9x+14=0$$ Use quadratic formula to find x. $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ the values of a, b nd c can be found by comparing the equation $$x^2-9x+14=0$$ with the general equation $$ax62+bx+c=0$$. Does that help? @BrainsNThings

3. ajprincess Group Title

*$$ax^2+bx+c=0$$