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BrainsNThings Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{x+2}+4=x\]
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
The first step u have to do in problems like this is to get rid of the sqrt. this can be done by squaring both sides. \(\sqrt{x+2}+4=x\) \(\sqrt{x+2}=x4\) \((\sqrt{x+2})^2=(x4)^2\) \(x+2=x^28x+16\) \(x^28xx+162=0\) \(x^29x+14=0\) Use quadratic formula to find x. \[x=\frac{b\pm\sqrt{b^24ac}}{2a}\] the values of a, b nd c can be found by comparing the equation \(x^29x+14=0\) with the general equation \(ax62+bx+c=0\). Does that help? @BrainsNThings
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.1
*\(ax^2+bx+c=0\)
 one year ago
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